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Slav-nsk
[51]
3 years ago
13
How many moles of Fe2O3 are in 209 g of the compound?
Chemistry
Answer
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1
answer:
Bezzdna
[24]
3 years ago
7
0
M = 209g
M = 56 * 2 + 16 * 3 = 160 g/mol
n = m/M = 209g / 160 g/mol = 1,30625mol
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