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Slav-nsk [51]
3 years ago
13

How many moles of Fe2O3 are in 209 g of the compound?

Chemistry
1 answer:
Bezzdna [24]3 years ago
7 0
M = 209g
M = 56 * 2 + 16 * 3 = 160 g/mol

n = m/M = 209g / 160 g/mol = 1,30625mol
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What is a non-example of an electrical conductor?
goblinko [34]

Answer: Sulphur, Phosphorus, Wood are non-conductors of electricity due to no presence of free electrons in outermost shell.

Explanation:

3 0
3 years ago
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He rate constant of a reaction is 4.55 × 10−5 l/mol·s at 195°c and 8.75 × 10−3 l/mol·s at 258°c. what is the activation energy o
Xelga [282]

Answer : The activation energy of the reaction is, 17.285\times 10^4kJ/mole

Solution :  

The relation between the rate constant the activation energy is,  

\log \frac{K_2}{K_1}=\frac{Ea}{2.303\times R}\times [\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = initial rate constant = 4.55\times 10^{-5}L/mole\text{ s}

K_2 = final rate constant = 8.75\times 10^{-3}L/mole\text{ s}

T_1 = initial temperature = 195^oC=273+195=468K

T_2 = final temperature = 258^oC=273+258=531K

R = gas constant = 8.314 kJ/moleK

Ea = activation energy

Now put all the given values in the above formula, we get the activation energy.

\log \frac{8.75\times 10^{-3}L/mole\text{ s}}{4.55\times 10^{-5}L/mole\text{ s}}=\frac{Ea}{2.303\times (8.314kJ/moleK)}\times [\frac{1}{468K}-\frac{1}{531K}]

Ea=17.285\times 10^4kJ/mole

Therefore, the activation energy of the reaction is, 17.285\times 10^4kJ/mole

8 0
3 years ago
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A chemist adds 36.0 g of sodium chloride to 200 g of water at STP and all of the sodium chloride dissolves. What is the solute i
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3 0
2 years ago
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The new fossil i.e, Fossil B (2,000 year old) contains more carbon-14 than the old fossil i.e, Fossil A (5,000 years old ) does.

<h3>What are Fossils ?</h3>

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Fossils are not just the remains of the organism But also the rocks.

Carbon 14 works to analyse the period organic remains that are between 100 years old (minimum) and about 50,000 years old, (maximum).

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2 years ago
Calculate molality,molarity and mole fraction of KI if the density of 20%(mass) aqueous KI is 1.202 g/mL
Scorpion4ik [409]
Basis: 1 L of the substance.
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                   mass solute = (1202 g) x 0.2 = 240.2 g
                   mass solvent = 1202 g x 0.8 =  961.6 g
                   moles KI = (240.2 g) x (1 mole / 166 g)  = 1.45 moles
                   moles water = (961.6 g) x (1 mole / 18 g) = 53.42 moles
1. Molality = moles solute / kg solvent 
                  = 1.45 moles / 0.9616 kg = 1.5 m
2. Molarity = moles solute / L solution
                  = 1.45 moles / 1 L solution = 1.45 M
3. molar mass = mole solute / total moles
                        =  1.45 moles / (1.45 moles + 53.42 moles) = 0.0264 

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