Answer:
Mole ratio for a compound
The chemical formula tells us the mole ratio.
CO2 = 1 CO2 molecule : 1 C atom : 2 O atoms.
Mole ratio for a reaction
The balanced chemical reactions tells us.
C12H22O11 + 12 O2 12 CO2 + 11 H2O
1 C12H22O11 molecule: 12 O2 molecules : 12 CO2
molecules : 11 H2O molecules.
Applications of the mole ratio concept
grams <--> moles <--> moles <--> grams
Explanation:
I also think it’s B but not quite sure
The HCl added = 1.25 moles
and the moles of Na2HPO4 = 1 mole
Now when acid is added in the given solution of Na2HPO4
One mole of H+ will react with one mole of Na2HPO4 to given one mole of NaH2PO4
Na2HPO4 + H+ ---> NaH2PO4
Now this one mole formed NaH2PO4 will further react with 0.25 moles of H+ left to form 0.25 moles of H3PO4 and 0.75 moles of NaH2PO4 will remain in the solution
So this will result into formation of a buffer of phosphoric acid and NaH2PO4
NaH2PO4 + H+ ---> H3PO4
pKa of H3PO4 = 2.1
so pH = pKa + log [salt] / [acid] = 2.1 + log [0.75 / 0.25] = 2.58
so the pH will be in between 2.1 to 7.2
1.3 x 10^21 atoms Na is 4.63230769231 mol Na
4.63230769231 mol Na * 23g/mol Na = 106.543076923g
The location of the negative charges is evenly distributed throughout the entire atom.
J. J. Tomson concluded that atoms are divisible and that the corpuscles are their building blocks.
Atoms are made up of smaller particles.
J. J. Thomson discovered the electron ( the negative charges of the atom) in 1897.
His "plum pudding" model (1904) suggested: the electrons are embedded in the positive charge and evenly distributed throughout the entire atom.
With this model, he abandoned his earlier hypothesis that the atom was composed of immaterial vortices.
Later, Rutherford demonstrate that J.J Thompson's Plum Pudding model was not accurate.
More info about Thomson’s plum pudding model: brainly.com/question/6319700
#SPJ4
