It is 800 N FN = 600N + 200 N = 800 N Answer to your question: The net force is all Newton's second law. It is the force that acts on a body or a particle. for example: It is the force we make when we push a car or something heavy that is in a straight line. .
5.610^-26 m is closest to the wavelength of the light.
E=K.E - Work function
hc/λ=1.10-4.65
hc/λ=3.50
λ=hc/3.50
λ=6.626×10 −34J⋅s×3×10^8
λ=5.610^-26 m
Because the relationship between wave frequency and wavelength is inverse, gamma rays have extremely short wavelengths that are only a fraction of the size of atoms, whereas other wavelengths can reach as far as the universe. Regardless of the medium they travel through, electromagnetic radiation's wavelengths are typically expressed in terms of the vacuum wavelength, even though this isn't always stated explicitly.
The wavelength of electromagnetic radiation affects its behavior. The speed of light is equal to wavelength times frequency. Frequency multiplied by the Planck constant equals energy. 1/wavelength is the wave number in cm. Along with the wavelengths of different parts of the electromagnetic spectrum, a rough estimation of the wavelength size is displayed.
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Answer:
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Explanation:
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Explanation:
Initial energy = final energy + work done by friction
PE = PE + KE + W
mgH = mgh + 1/2 mv² + W
(800)(9.8)(30) = (800)(9.8)(2) + 1/2 (800) v² + 25000
v = 22.1 m/s
Without friction:
PE = PE + KE
mgH = mgh + 1/2 mv²
(800)(9.8)(30) = (800)(9.8)(2) + 1/2 (800) v²
v = 23.4 m/s
Answer:
That scenario can be explained by the idea of the contribution of dark matter on that point.
Explanation:
It can be explained through the idea of dark matter, this one was born to explain why stars (or any object) that were farther for the supermassive black hole in the center of the Milky Way galaxy didn't decrease it rotational velocity as it was expected according to equation 1.
(1)
Where v is the rotational velocity, G is the gravitational constant, M is the mass of the supermassive black hole, and r is the orbital radius.
Notice, that If the distance increases the orbital speed decreases (inversely proportional).