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2 years ago

4) You have a spring-loaded air rifle. When it is loaded, the spring is

Physics

1 answer:

Dafna1 [17]2 years ago

5 0

The potential energy of the spring is 6.75 J

Explanation:

The elastic potential energy stored in a spring is given by the equation:

$E=\frac{1}{2}kx^2$

where

k is the spring constant

x is the compression/stretching of the string

For the spring in this problem, we have:

k = 150 N/m is the spring constant

x = 0.3 m is the compression

Substituting, we find

$E=\frac{1}{2}(150)(0.3)^2=6.75 J$

Learn more about potential energy:

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What is the period of a wave that has a frequency of 300 hz?

Butoxors [25]

Answer:

T = 0.003 s

(Period is written as T)

Explanation:

Period = time it takes for one wave to pass (measured in seconds)

frequency = number of cycles that occur in 1 second

(measured in Hz / hertz / 1 second)

Period : T

frequency : f

So, if we know that the frequency of a wave is 300 Hz, we can find the period of the wave from the relation between frequency and period

T = $\frac{1}{f}$ f = $\frac{1}{T}$

to find the period (T) of this wave, we need to plug in the frequency (f) of 300

T = $\frac{1}{300}$

T = 0.00333333333

So, the period of a wave that has a frequency of 300 Hz is 0.003 s

[the period/T of this wave is 0.003 s]

3 0

1 year ago

(a) Calculate the buoyant force on a 2.00-L helium balloon.

iragen [17]

Answer:

0.0239364 N

0.0057879 N

Explanation:

$\rho$ = Density of the gas

g = Acceleration due to gravity = 9.81 m/s²

V = Volume

Mass of rubber = 1.5 g

Buoyant force is given by

$F_b=\rho gV\\\Rightarrow F_b=1.22\times 9.81\times 2\times 10^{-3}\\\Rightarrow F_b=0.0239364\ N$

The buoyant force is 0.0239364 N

Net vertical force is given by

$F_n=F_b-W_{He}-W_{r}\\\Rightarrow F_n=0.0239364-0.175\times 2\times 10^{-3}\times 9.81-1.5\times 10^{-3}\times 9.81\\\Rightarrow F_n=0.0057879\ N$

The net vertical force is 0.0057879 N

6 0

3 years ago

The increase in height as a tsunami approaches shore is due to

ryzh [129]

Answer:

C. The decrease in speed as the wave approaches shore.

Explanation:

The waves break when approaching the shore because the depth decreases. Thus, the wave travels more slowly and increases its height. There comes a time when the part of the wave on the surface travels faster than the one that travels under water, the ridge destabilizes and falls against the ground.

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2 years ago

Read 2 more answers

A 50 Kg box sits at rest on a 30 degree ramp where the coef of static friction is 0.5773. If your push was directed at an angle

emmasim [6.3K]

Given data:

m= 50 Kg,

W= m×g = 50 × 9.81 = 490.5 N

ramp angle (α) = 30 degrees,

coefficient of friction (μs) = 0.5773,

Push at an angle (Θ) = 40 degrees,

Determine: Push to get box move up (P)=?

From the figure,

Resolving the forces along the plane

W sinα + μs.R = P cos Θ --------------------- (i)

Resolving the forces perpendicular to the inclined plane

W cosα = R+Psin Θ => R= W cosα - Psin Θ -------------- (ii)

Solving (i) and (ii) and keeping μs = tan Φ, Φ = Θ 

Pmin = W sin( α +Θ )

= W[ sin α.Cos Θ + cos α.sin Θ]

= 490.5 [ (sin 30.cos40) + (cos30.sin 40)]

= 460.9 N

Minimum push required to move the box up the ramp is 460.9 N

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3 years ago

Your bike starts with an initial velocity of 1 m/s and you accelerate to 4 m/s in 6 seconds. How far did you travel while accele

garri49 [273]

Answer:

78 m

Explanation:

Initial v = 1 m/s

a = 4 m/s²

t = 6s

$x = v_{i} t + \frac{1}{2}at^{2} \\x = (1)(6) + \frac{1}{2} (4)(6)^{2} \\x = 6 + 72\\x = 78$

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2 years ago