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11111nata11111 [884]
3 years ago
10

Express newton pascal joule and watt in fundamental unit​

Physics
1 answer:
Nadya [2.5K]3 years ago
3 0

i added an image. i hope it helped :)

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The surface of the Sun has a temperature of about 5 800 K. If the radius of the Sun is 7 × 108 m, determine the power output of
Nimfa-mama [501]

Answer:

a. 3.95\times10^{26}W

Explanation:

T = temperature of the surface of sun = 5800 K

r = Radius of the Sun = 7 x 10⁸ m

A = Surface area of the Sun

Surface area of the sun is given as

A = 4\pi r^{2} \\A = 4(3.14) (7\times10^{8})^{2}\\A = 6.2\times10^{18} m^{2}

e = Emissivity = 1

\sigma = Stefan's constant = 5.67 x 10⁻⁸ Wm⁻²K⁻⁴

Using Stefan's law, Power output of the sun is given as

P = \sigma e AT^{4} \\P = (5.67\times10^{-8}) (1) (6.2\times10^{18}) (5800)^{4}\\P = 3.95\times10^{26} W

4 0
3 years ago
If 3,600 J of work is done in 3.0 s, what is the power?
Firlakuza [10]

Answer:

1,200 watts

Explanation:

1 watt = 1 Joule (J) of work / second

So, 3600 Joules of work / 3 seconds is:

3600 J / 3 seconds = 1,200 watts

8 0
3 years ago
The hairdryer has a plastic case so there is no need for an earth wire connection in the plug.
kolbaska11 [484]
Gravitational attraction / field strength increases when closer; A light dependent resistor (LDR) can be used as a sensor to detect light intensity.
4 0
3 years ago
They are adding steel components to the roof supports of the structure. We know that steel elongates when heated. At what temper
Andru [333]

Answer:

The change in temperature of 576.9°C will produce an elongation of 9 inches per feet in steel.

Explanation:

The formula for linear expansion of a material is:

ΔL = αLΔT

where, ΔL = change in length

             L = Original length

           ΔT = Change in temperature

             α = coefficient of linear expansion

For steel, α = 13 x 10^-6 /°C

                L = 100 ft

                ΔL = (9 in)(1 ft/12 in) = 0.75 ft

Therefore,

0.75 ft = (13 x 10^-6 /°C)(100 ft)ΔT

<u>ΔT = 576.9°C</u>

<u></u>

8 0
3 years ago
At t= 0, a particle moving in the xy plane with constant acceleration has a velocity of Vi= (3.00i -2.00j) m/s and is at the ori
ivanzaharov [21]

Answer:

(a) a = (2i + 4.5j) m/s^2

(b) r = ro + vot + (1/2)at^2

Explanation:

(a) The acceleration of the particle is given by:

\vec{a}=\frac{\vec{v}-\vec{v_o}}{t}\\\\

vo: initial velocity = (3.00i -2.00j) m/s

v: final velocity = (9.00i + 7.00j) m/s

t = 3s

by replacing the values of the vectors and time you obtain:

\vec{a}=\frac{1}{3s}[(9.00-3.00)\hat{i}+(7.00-(-2.00))\hat{j}]\\\\\vec{a}=(2\hat{i}+4.5\hat{j})m/s^2

(b) The position vector is given by:

\vec{r}=\vec{r_o}+\vec{v_o}t+\frac{1}{2}\vec{a}t^2

where vo = (3.00i -2.00j) m/s and a = (2.00i + 4.50j)m/s^2

4 0
2 years ago
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