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Mekhanik [1.2K]

3 years ago

6

A new planet is discovered in an approximately circular orbit beyond Pluto. It moves at a rate of approximately 1° per year. It'

s semi-major axis is approximately

1 answer:

Mazyrski [523]3 years ago

6 0

A new planet is discovered in an approximately circular orbit beyond Pluto. It moves at a rate of approximately 1° per year. It's semi-major axis is approximately:
answer:::::50 AU

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During normal beating, the heart creates a maximum 3.60 mV potential across 0.250 m of a person's chest, creating a 1.00 Hz elec

grandymaker [24]

Answer:

The maximum electric field strength is 0.0144 V/m.

Explanation:

Given that,

Electric potential created in the heart, V = 3.6 mV

Distance, d= 0.25 m

Frequency of the the electromagnetic wave, f = 1 Hz

We need to find the maximum electric field strength created. We know that the electric potential is given by :

$V=Ed$

E is the maximum electric field strength

$E=\dfrac{V}{d}\\\\E=\dfrac{3.6\times 10^{-3}\ V}{0.25\ m}\\\\E=0.0144\ V/m$

So, the maximum electric field strength is 0.0144 V/m. Hence, this is the required solution.

5 0

3 years ago

A particle travels along the curve from A to B in 5 s. It takes 8 s for it to go from B to C and then 10 s to go from C to A. De

Elza [17]

Answer:

5.1 m/s

Explanation:

The figure is missing: find it in attachment.

In order to find the average speed, we have to calculate the length of the total path, and divide it by the total time elapsed.

The curve from A to B is a quarter of a circle with a radius of r = 20 m, so its length is:

$AB=\frac{\pi r}{2}=\frac{\pi (20)}{2}=31.4 m$

The path BC is the hypothenuse of a right triangle with sides equal to 20 m and 30 m, so its length is

$BC=\sqrt{30^2+20^2}=36 m$

Finally, the length of the path AC is the sum of the side of 30 m and the radius of the curve, so

$AC=30 + 20 = 50 m$

So the total distance covered is

$d=AB+BC+AC=31.4+36+50=117.4 m$

The total time elapsed is

$t=5 s + 8 s + 10 s =23 s$

So, the average speed is

$v=\frac{d}{t}=\frac{117.4}{23}=5.1 m/s$

6 0

3 years ago

Consider a cylindrical specimen of some hypothetical metal alloy that has a diameter of 8.0 mm. A tensile force of 1000 N produc

Dimas [21]

Answer:

1.7 × 10^11 Pa

Explanation:

Please see the attachments below

3 0

3 years ago

A solid sphere, solid cylinder, and a hollow pipe all have equal masses and radii. If the three of them are released simultaneou

Roman55 [17]

Answer:

The solid sphere will reach the bottom first.

Explanation:

In order to develop this problem and give it a correct solution, it is necessary to collect the concepts related to energy conservation. To apply this concept, we first highlight the importance of conserving energy so we will match the final and initial energies. Once this value has been obtained, we will concentrate on finding the speed, and solving what is related to the Inertia.

In this way we know that,

$\Delta KE = - \Delta PE$

$KE_t + KE_r = mgh$

We know as well that the lineal and angular energy are given by,

$KE_r = \frac{1}{2}I\omega^2$

And the tangential kinetic energy as

$KE_t = \frac{1}{2} mv^2$

Where $\omega = \frac{v}{R}$

Replacing

$\frac{1}{2}mv^2 + \frac{1}{2}I\frac{v}{R} = mgh$

Re-arrange for v,

$v=\sqrt{\frac{2mgh}{m+I/R^2}}$

We have here three different objects: solid cylinder, hollow pipe and solid sphere. We need the moment inertia of this objects and replace in the previous equation found, then,

For hollow pipe:

$I_{hp}=mR^2$

$v_{hp}=\sqrt{\frac{2mgh}{m+(mR^2)/R^2}}$

$v_{hp}=\sqrt{\frac{2mgh}{m+m)}$

$v_{hp}=\sqrt{gh}$

For solid cylinder:

$I_{sc}=\frac{1}{2}mR^2$

$v_{sc}=\sqrt{\frac{2mgh}{m+(1/2mR^2)/R^2}}$

$v_{sc}=\sqrt{\frac{2mgh}{m+1/2m}}$

$v_{sc}=\sqrt{\frac{3}{4}gh}$

For solid sphere,

$I_{ss}=\frac{2}{5}mR^2$

$v_{ss}=\sqrt{\frac{2mgh}{m+(2/5mR^2)/R^2}}$

$v_{ss}=\sqrt{\frac{2mgh}{m+2/5m}}$

$v_{ss}=\sqrt{\frac{10}{7}gh}$

Then comparing the speed of the three objects we have:

$v_{hp}$

$\sqrt{gh}$

3 0

4 years ago

Find the work done by a man who is pulling a box of 45kg of mass by means of rope which makes angle of 45 degrees.

Juli2301 [7.4K]

Answer:

0

Explanation:

Since no distance is given, the force is not doing any work

No work is done by the man since we do not know the distance or displacement.

Work is only said to be done when the force applied on an object moves it through a particular distance.

Work done = Force x distance.

Since no distance is given in this problem, we can as well assume that the force applied is doing no work on the object.

4 0

3 years ago