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777dan777 [17]
4 years ago
10

As a rough approximation, the human body may be considered to be a cylinder of length L=2.0m and circumference C=0.8m. (To simpl

ify things, ignore the circular top and bottom of the cylinder, and just consider the cylindrical sides.) If the emissivity of skin is taken to be e=0.6, and the surface temperature is taken to be T=30∘C, how much thermal power P does the human body radiate?
Physics
1 answer:
Brilliant_brown [7]4 years ago
4 0

Answer:

Thermal Power = 460W

Explanation:

From Stephan-Boltzmann Law Formula;

P = єσT⁴A

Where,

P = Radiation energy

σ = Stefan-Boltzmann Constant

T = absolute temperature in Kelvin

є = Emissivity of the material.

A=Area of the emitting body

Now, σ = 5.67 x 10^(-8)

є = 0.6

Temperature = 30°C and coverting to kelvin = 30 + 273 = 303K

Area ; since we are to consider the sides of the human body as 2m and 0.8m,thus area = 2 x 0.8 = 1.6

Thus thermal power = 0.6 x 5.67 x 10^(-8) x303⁴ x 1.6 = 458. 8W

Normally, we approximate to the nearest 10W. Thus, thermal power is approximately 460W

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Y_Kistochka [10]

1) Potential energy before the fall: 98 J

The gravitational potential energy of an object is given by:

U=mgh

where m is the mass of the object, g is the gravitational acceleration and h the heigth of the object above the ground.

In this problem, m = 2 kg, g = 9.8 m/s^2 and h = 5 m: substituting into the equation, we find

U=(2 kg)(9.8 m/s^2)(5 m)=98 J


2) Work done by gravity: 98 J

The work done by a force is given by:

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the direction of the force and the displacement

In this problem:

F=mg=(2 kg)(9.8 m/s^2)=19.6 N

d = 5 m

\theta=0^{\circ}

Therefore,

W=(19.6 N)(5 m)(cos 0^{\circ})=98 J

5 0
3 years ago
A solid sphere of radius 42 cm has a total positive charge of 23 µC uniformly distributed throughout its volume. Calculate the m
ludmilkaskok [199]

Answer:

Electric field due to uniformly charged sphere is 9.2 x 10⁴ N/C

Explanation:

Given :

Radius of the solid sphere, R = 42 cm = 0.42 m

Total charge on the sphere, Q = 23 μC = 23 x 10⁻⁶ C

Distance of the point from the center of the sphere, r = 150 cm = 1.5 m

Since, r > R, so the point is outside the sphere. Thus, the electric field outside the uniformly charged sphere is determine by the relation:

E=\frac{kQ}{r^{2} }

Here k is constant and its value is 9 x 10⁹ N·m²/C².

Substitute the suitable values in the above equation.

E=\frac{9\times10^{9}\times23\times10^{-6}  }{(1.5)^{2} }

E = 9.2 x 10⁴ N/C

5 0
3 years ago
A book falls of the table and hits the floor. Is work done? Why?​
morpeh [17]

<u>Yes, work is done when a book falls of the table.</u>

This is because:

When the book falls, it's potential energy is converted into kinetic energy.   As it reaches the floor down, this kinetic energy is converted to heat energy and sound energy due to the impact.

When a force is imposed on an object to cause displacement of that object, work is done on that object. For a force to do work on an object, there should be a displacement and this force should cause the displacement. So here, since the book falls from the table and causes the displacement of the book from the table to the floor. It is said that work is done.

Work can be given by the formula:

W = F • d

where F is the force and d is the displacement.

6 0
3 years ago
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A force of 20N acts upon a body whose weight is 9.8 N. What is the mass of the body and how much is its acceleration?
zloy xaker [14]

Answer:

Explanation:

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7 0
3 years ago
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Gold has a density of 19.32 g/cm 3 . If you cut a piece of gold in half, the density of each piece will be
maksim [4K]

Answer:

See Explanation

Explanation:

The density of a substance is an intrinsic property. Intrinsic properties are properties that are characteristic of a material. It does not depend on the amount of substance present.

Since density is an intrinsic or intensive property, If you cut a piece of gold in half, the density of each piece will still be 19.32 g/cm 3 because density does not depend on the size of the gold piece.

3 0
3 years ago
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