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OlgaM077 [116]
3 years ago
6

How many pairs of angles are marked as congruent in the figures below?

Mathematics
2 answers:
Sladkaya [172]3 years ago
6 0

Answer:

I got C. 2

Step-by-step explanation:

I finished the test ( :

MrRissso [65]3 years ago
5 0

Answer:2

Step-by-step explanation:According to the diagram,there is a single angle marking for one pair of angles V and M,a double angle marking for angles X and L.

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Solve for x
ludmilkaskok [199]

Answer:

x = 3/4

Step-by-step explanation:

Step 1: Write equation

5x - 2(x + 1) = 1/4

Step 2: Solve for <em>x</em>

  1. <u>Distribute -2:</u> 5x - 2x - 2 = 1/4
  2. <u>Combine like terms:</u> 3x - 2 = 1/4
  3. <u>Add 2 to both sides:</u> 3x = 9/4
  4. <u>Divide both sides by 3:</u> x = 3/4

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

5(3/4) - 2(3/4 + 1) = 1/4

15/4 - 2(7/4) = 1/4

15/4 - 14/4 = 1/4

1/4 = 1/4

3 0
3 years ago
How many different ways can the line above be named? What are those names?
suter [353]
Its either 3 or 2 
the third way matches only if there's another reference  line 
I'll go with 3


7 0
3 years ago
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According to the graph the system of linear equations has how many solutions
Maurinko [17]

Answer:

infinitely many

6 0
3 years ago
What is the answer to -5/8x+1/4=1/8
natali 33 [55]

Answer:B

Step-by-step explanation:

3 0
3 years ago
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A real estate company wants to build a parking lot along the side of one of its buildings using 800 feet of fence. If the side a
Elden [556K]

Answer:

80,00ft^{2}

Step-by-step explanation:

According to my research, the formula for the Area of a rectangle is the following,

A = L*W

Where

  1. A is the Area
  2. L is the length
  3. W is the width

Since the building wall is acting as one side length of the rectangle. We are left with 1 length and 2 width sides. To maximize the Area of the parking lot we will need to equally divide the 800 ft of fencing between the <u>Length and Width.</u>

800 / 2 = 400ft

So We have 400 ft for the length and 400 ft for the width. Since the width has 2 sides we need to divide 60 by 2.

400/2 = 200 ft

Now we can calculate the maximum Area using the values above.

A = 400ft*200ft

A = 80,000ft^{2}

So the Maximum area we are able to create with 800 ft of fencing is 80,00ft^{2}

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

Read more on Brainly.com - brainly.com/question/12953427#readmore

3 0
3 years ago
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