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Mice21 [21]
3 years ago
7

HELP ALSO DONT CLICK THE LINKS THIS GUY IS PUTTING

Mathematics
2 answers:
Hitman42 [59]3 years ago
7 0

Answer:

What do you need help with?

hodyreva [135]3 years ago
3 0

Answer:

where's the question you need help with??

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The number of hours of daylight measured in one year in Ellenville can be modeled by a sinusoidal function. During 2006, (not a
Kamila [148]

Answer:

f ( t ) = 3.7*sin ( 0.01736*t ) + 12

Step-by-step explanation:

Solution:-

- We are to model a sinusoidal function for the number of hours of daylight measured in one year in Ellenville.

- We will express a general form of a sinusoidal function [ f ( t ) ] as follows:

                                f ( t ) = A*sin ( w*t ) + c

Where,

                  A: The amplitude of the hours of daylight

                  w: The angular frequency of occurring event

                  c: The mean hours of daylight

                  t: The time taken from reference ( days )

- We are given that the longest day [ f ( t_m_a_x ) ] occurred on June 21st and the shortest day [ f ( t_m_i_n ) ] on December 21st.

- The mean hours of daylight ( c ) is the average of the maximum and minimum hours of daylight as follows:

                              c = \frac{f(t_m_a_x ) +f(t_m_i_n )  }{2} \\\\c = \frac{15.7 + 8.3}{2} = \frac{24}{2} \\\\c = 12

- The amplitude ( A ) of the sinusoidal function is given by the difference of either maximum or minimum value of the function from the mean value ( c ):

                              A = f ( t_m_a_x ) - c\\\\A = 15.7 - 12\\\\A = 3.7

- The frequency of occurrence ( w ) is defined by the periodicity of the function. In other words how frequently does two maximum hours of daylight occur or how frequently does two minimum hours of daylight occur.

- The time period ( T ) is the time taken between two successive maximum duration of daylight hours. We were given the longest day occurred on June 21st and the shortest day occurred on December 21st. The number of days between the longest and shortest day will correspond to half of the time period ( 0.5*T ):

                              0.5*T = 7 + 31 + 31 + 30 +31 +30 +21\\\\T = 2* [ 181 ] \\\\T = 362 days

- The angular frequency ( w ) is then defined as:

                              w = \frac{2\pi }{T} = \frac{2\pi }{362}  \\\\w = 0.01736

- We will now express the model for the duration of daylight each day as function of each day:

                              f ( t ) = 3.7*sin ( 0.01736*t ) + 12

               

8 0
4 years ago
7th grade math
maw [93]

Answer:

Can you please post a picture...it will help me understand it more!

Step-by-step explanation:

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He can put 4 kids in each of 9 cars and then leave the 10th car empty. Or put 2 kids in 9th car and 2 kids in 10th so all the cars would be filled
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4/9 x 3/8, is each product would be less than or greater than the first factor
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Write a correspoding real world problemas TO represent 2x - 125 = 400
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