Question

What is the point-slope form of the line with slope 2/5 that passes through the point (-4, -7) ?

Answer 1

Answer:

• General equation of a line:

${ \tt{y = mx + b}}$

• m is the slope, m = 2/5
• b is y-intercept

${ \tt{ - 7 = ( \frac{2}{5} \times - 4) + b }} \\ \\ { \tt{ - 7 = - \frac{8}{5} + b}} \\ \\ { \tt{b = - \frac{27}{5} }}$

• Therefore, equation of line is:

${ \tt{y = \frac{2}{5}x - \frac{27}{5} }}$

Answer 2

Answer:

y + 7 = $\frac{2}{5}$ ( x + 4 )

Step-by-step explanation:

( $x_{1}$ , $y_{1}$ )

y - $y_{1}$ = $\frac{2}{5}$ ( x - $x_{1}$ )

~~~~~~~~~~~~~~

( - 4 , - 7 )

y - ( - 7 ) = $\frac{2}{5}$ ( x - ( - 4 ))

y + 7 = $\frac{2}{5}$ ( x + 4 )