Explanation:
1st one will be cathodic reaction and reduction will occur since electrons are being gained and hydrogen goes from +1 to zero oxidation state.
2nd one will be anodix reaction and oxidation will take place because Iodide ion's oxidation number increases from -1 to 0
Answer:
a. syn
b. E1
c. E2
d. E2
Explanation:
In organic chemistry, the rule of Saytzeff, Saytzev or Zaitsev states that in an elimination reaction (β-elimination) in which more than one alkene can be formed, the most thermodynamically stable will be the majority.
In general, the most substituted alkene is the most stable, due to the electronic sharing properties of the alkyl groups with the double bond C = C (hyper-conjugation). Also, in some cases, another stabilizing effect may be incurred when establishing the regioselectivity such as the conjugation of the double bond with other groups.
This rule is valid except in bimolecular elimination reactions (E2) in which there is a significant steric hindrance, branched substrate and / or bulky base, and without the possibility of conjugation, then applying Hofmann's rule.
The elimination reaction E1 has a potential energy profile similar to that of an SN1 reaction. The formation step of carbocation is very endothermic, with a transition state which is what determines the speed of the reaction. The second step is a rapid and exothermic deprotonation. Base does not participate in the step that determines the speed of the process, so it only depends on the concentration of alkyl halide.
The bimolecular elimination E2 takes place without intermediates and consists of a single ET, in which the base abstracts the proton, the leaving group leaves and the two carbons involved are rehybridized from sp3 to sp2.
A pH of 7 or lower makes something an acid so it would be 3
Answer:
The player then exerts a force that is equal in magnitude (the size of a force) and opposite in direction. This slows down the ball
Explanation:
you can use friction friction (a force applied on the ball in the opposite direction to its motion), but the direction of its motion will remain the same.
Explanation:
Alkali metals forms the group 1 of the modern periodic table. They include Lithium, sodium, potassium, rubidium, cesium, and francium.
The general electronic configuration of the alkali metals -
. They have 1 valence electron.
Ionization energy is the minimum amount of energy which is required to knock out the loosely bound valence electron from the isolated gaseous atom.
<u>Thus, removal of the valence electron leads to the alkali metals having noble gas electronic configuration and which is stable. Thus, the removal of the second electron is very tough and thus, there a large increase between the first and second ionization energies of the alkali metals.</u>
