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Ahat [919]
2 years ago
15

Which must be the same when comparing 1 mol of oxygen gas, O2, with 1 mol of carbon monoxide gas, CO? the mass the volume the nu

mber of molecules the number of oxygen atoms
Chemistry
2 answers:
Phoenix [80]2 years ago
6 0

Answer : The correct option is, the number of molecules.

Explanation :

As we are given that 1 mole of oxygen gas, (O_2) and 1 mole of carbon monoxide gas, (CO).

From the given options, the number of molecules must be same when comparing 1 mole of oxygen gas, (O_2) and 1 mole of carbon monoxide gas, (CO) because there are 2 molecules present in both oxygen gas and carbon monoxide gas.

The mass of 1 mole of oxygen gas, (O_2) is, 32 g and the mass of 1 mole of carbon monoxide gas, (CO) is, 28 g. So, the mass will not be same.

The number of oxygen atoms in 1 mole of oxygen gas, (O_2) is, 2\times 6.022\times 10^{23} and the number of oxygen atoms in 1 mole of carbon monoxide gas, (CO) is, 1\times 6.022\times 10^{23}. So, the number of oxygen atoms will not be same.

The volume of 1 mole of oxygen gas, (O_2) and 1 mole of carbon monoxide gas, (CO) will not be same due to the difference in the masses.

Hence, the correct option is, the number of molecules.

jekas [21]2 years ago
3 0
The number of molecules because 1 mol is equal to 6.02x10^23 molecules, therefore they both have the same amount of molecules because they both have 1 mol
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3 years ago
For the chemical reaction CaI2+2AgNO3-> 2AgI+Ca(NO3)2 how many moles of silver iodide will be produced from 205g of calcium i
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Answer:

Moles of silver iodide produced = 1.4 mol

Explanation:

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Mass of calcium iodide = 205 g

Moles of silver iodide produced = ?

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Chemical equation:

CaI₂ + 2AgNO₃     →      2AgI + Ca(NO₃)₂

Number of moles calcium iodide:

Number of moles = mass/ molar mass

Number of moles = 205 g/ 293.887 g/mol

Number of moles = 0.7 mol

Now we will compare the moles of calcium iodide with silver iodide.

                     CaI₂         :           AgI

                         1           :             2

                       0.7         :           2×0.7 = 1.4

Thus 1.4 moles of silver iodide will be formed from 205 g of calcium iodide.

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3 years ago
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