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Ahat [919]
3 years ago
15

Which must be the same when comparing 1 mol of oxygen gas, O2, with 1 mol of carbon monoxide gas, CO? the mass the volume the nu

mber of molecules the number of oxygen atoms
Chemistry
2 answers:
Phoenix [80]3 years ago
6 0

Answer : The correct option is, the number of molecules.

Explanation :

As we are given that 1 mole of oxygen gas, (O_2) and 1 mole of carbon monoxide gas, (CO).

From the given options, the number of molecules must be same when comparing 1 mole of oxygen gas, (O_2) and 1 mole of carbon monoxide gas, (CO) because there are 2 molecules present in both oxygen gas and carbon monoxide gas.

The mass of 1 mole of oxygen gas, (O_2) is, 32 g and the mass of 1 mole of carbon monoxide gas, (CO) is, 28 g. So, the mass will not be same.

The number of oxygen atoms in 1 mole of oxygen gas, (O_2) is, 2\times 6.022\times 10^{23} and the number of oxygen atoms in 1 mole of carbon monoxide gas, (CO) is, 1\times 6.022\times 10^{23}. So, the number of oxygen atoms will not be same.

The volume of 1 mole of oxygen gas, (O_2) and 1 mole of carbon monoxide gas, (CO) will not be same due to the difference in the masses.

Hence, the correct option is, the number of molecules.

jekas [21]3 years ago
3 0
The number of molecules because 1 mol is equal to 6.02x10^23 molecules, therefore they both have the same amount of molecules because they both have 1 mol
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3 years ago
If a container were to have 24 molecules of C5H12 and 24 molecules of O2 initially, how many total molecules (reactants plus pro
frutty [35]

Answer:

81 molecules

Explanation:

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Aplying the conditins of the question; 24 molecules each of C5H12 and O2 we have;

3C5H12 + 24O2 --> 15CO2 + 18H2O

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Total molecules is given as;

3(C5H12) + 24(O2) + 15(CO2) + 18(H2O) + 21(Unreacted C5H12) = 81 molecules

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