Answer:
31.58 L
Explanation:
From the question given above, the following data were obtained:
Initial mole (n₁) of gas = 1.90 moles
Initial volume (V₁) = 40 L
Final mole (n₂) = 1.90 – 0.40 = 1.5 moles
Final volume (V₂) =.?
The final volume of the gas can be obtained as follow;
V₁ / n₁ = V₂ / n₂
40 / 1.9 = V₂ / 1.5
Cross multiply
1.9 × V₂ = 40 × 1.5
1.9 × V₂ = 60
Divide both side by 1.9
V₂ = 60 / 1.9
V₂ = 31.58 L
Thus, the final volume of the gas is 31.58 L
Answer:
63.616
Explanation:
DATA
1. first atomic mass;m1=63
- second atomic mass;m2=65
- first percentage;p1= 69.2%
- second percentage me;p2=30.8%
- average mass;avg= ?
SOLUTION
avg=<u> (m1)(p1) + (m2)(</u><u>p2</u><u>)</u>
100
avg= <u>(63)(69.2) + (65)(30.8)</u>
100
avg= <u>4</u><u>3</u><u>5</u><u>9</u><u>.</u><u>6</u><u> </u><u>+</u><u> </u><u>2</u><u>0</u><u>0</u><u>2</u>
100
avg= <u>6361.6</u>
100
avg= 63.616
1. Answer;
Equation;
-NaCl(aq) → Na{+}(aq) + Cl{-}(aq)
Explanation;
-The polar property of water allows ionic compounds such as sodium chloride to dissolve in water. (sodium chloride is an ionic compound).
-Sodium chloride dissociates in water into sodium ions and chloride ions as shown by the equation. Water molecules surrounds the negatively charged chloride ions and positive sodium ions and pulls them away into solution.
2. Answer;
Equation;
Fe(ClO4)3(aq) → Fe 3+(aq) + 3ClO4 - (aq)
Explanation;
Iron (iii) perchlorate (Fe(ClO4)3 dissociates in water into iron (iii) ion and perchlorate ion. Iron (iii) ion is positively charged while the perchlorate ion is negatively charged, they are pulled apart by the polar water molecules, a process called dissociation.
-
Answer : The amount of heat needed is, 1188 J
Explanation :
Formula used :
![q=m\times c\times (T_2-T_1)](https://tex.z-dn.net/?f=q%3Dm%5Ctimes%20c%5Ctimes%20%28T_2-T_1%29)
where,
q = heat needed = ?
m = mass of copper = 55 g
c = specific heat capacity of copper = ![0.40J/g^oC](https://tex.z-dn.net/?f=0.40J%2Fg%5EoC)
= initial temperature = ![20.0^oC](https://tex.z-dn.net/?f=20.0%5EoC)
= final temperature = ![74.0^oC](https://tex.z-dn.net/?f=74.0%5EoC)
Now put all the given values in the above formula, we get:
![q=55g\times 0.40J/g^oC\times (74.0-20.0)^oC](https://tex.z-dn.net/?f=q%3D55g%5Ctimes%200.40J%2Fg%5EoC%5Ctimes%20%2874.0-20.0%29%5EoC)
![q=1188J](https://tex.z-dn.net/?f=q%3D1188J)
Thus, the amount of heat needed is, 1188 J