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solniwko [45]
3 years ago
12

A sample of chlorine gas occupies a volume of 707 ml at 2.90 atm. What is the new pressure in torr if the volume is compressed t

o 0.533 L?
a: 3,850 torr
b: 3.85 torr
c: 291 torr
d: 2,920 torr
Chemistry
1 answer:
dolphi86 [110]3 years ago
3 0

Answer:

The new pressure is 3850 torr.  

Explanation:

The relation between volume and pressure is inverse as per Boyle's law. Its mathematical form is given by :

P_1V_1=P_2V_2

Here,

P_1=2.9\ atm

V_1=707\ mL

V_2=0.533\ L

Let P_2 is the new pressure. So using Boyle's law we get :

P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{2.9\times 707}{0.533}\\\\P_2=3846.71\ \text{torr}

or

P_2=3850\ \text{torr}

So, the new pressure is 3850 torr.  

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Slicing an average loaf of bread gives 13 medium thickness slices. Each slice of bread is to be coated with 0.0500 oz of mayonna
AlexFokin [52]

Answer:

36 loaves of bread and 18.48 ounces of mayonnaise are needed to make all of the sandwiches.

Explanation:

Number of slices of ham = 231

Given that each sandwich has 1 slice of ham.

Then 231 slices of ham will be in :

1\times 231 =231 sandwiches

A single sandwich is made up of 2 bread slices , Then bread slices in 231 sandwiches will be :

231\times 2=462

Each bread slice is applied with 0.0500 ounce of mayonnaise.

Then 462 bread slices will have :

462\times 0.0500 ounces=18.48 Oz

1 bread loaf = 13 bread slices

Then breads loves in 462  bread slices :

\frac{462}{13}=35.54\approx 36

36 loaves of bread and 18.48 ounces of mayonnaise are needed to make all of the sandwiches.

8 0
4 years ago
One gram of liquid benzene is burned in a bomb calorimeter. The temperature before ignition was 20.826 C, and the temperature af
Licemer1 [7]

Answer:

fH = - 3,255.7 kJ/mol

Explanation:

Because the bomb calorimeter is adiabatic (q =0), there'is no heat inside or outside it, so the heat flow from the combustion plus the heat flow of the system (bomb, water, and the contents) must be 0.

Qsystem + Qcombustion = 0

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10000*(25.000 - 20.826) + Qc = 0

Qcombustion = - 41,740 J = - 41.74 kJ

So, the enthaply of formation of benzene (fH) at 298.15 K (25.000 ºC) is the heat of the combustion, divided by the number of moles of it. The molar mass od benzene is: 6x12 g/mol of C + 6x1 g/mol of H = 78 g/mol, and:

n = mass/molar mass = 1/ 78

n = 0.01282 mol

fH = -41.74/0.01282

fH = - 3,255.7 kJ/mol

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Zielflug [23.3K]

Answer:

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