Answer:
0.66
Step-by-step explanation:
The exponential growth equation is expressed as;
S(t) = S0e^kt
S(t) is the number of stores after t years
S0 is the initial number of stores
If a chain of retail computer stores opened 2 stores in its first year of operation then at t = 1, S(t) = 2. Substitute into the equation;
2 = S0e^k(1)
2 = S0e^k .... 1
Also if after 8 years of operation, the chain consisted of 206 stores, this means at t = 8, S(t) = 206. Substitute into the equation;
206 = S0e^k(1)
206 = S0e^8k .... 2
Next is to calculate the value of k
Divide equation 2 by 1;

Hence the value of k to the nearest hundredth is 0.66
Answer:

Step-by-step explanation:








Answer:
3526
Step-by-step explanation:
4300×3%=129
129×6=774
4300_774= 3526
Answer:
9
Step-by-step explanation:
So first I created 2 distance forumlas and set them equal to each other

then I simplified them





when k = 9, the two distances are equal
Answer:
80/100
or
8/10
or
4/5
Step-by-step explanation: