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geniusboy [140]

3 years ago

13

Solve the following inequality. Then place the correct answer in the box provided. Answer in terms of a mixed number. 2(P +1) +

3(P + 2 ) > 2

1 answer:

Darina [25.2K]3 years ago

6 0

Answer:

$P>-\frac{6}{5}$

Step-by-step explanation:

Isolate the variable by dividing each side by factors that dont't contain the variable.

$2(P+1)+3(P+2)>2$

$2P+2+3P+6>2$

$5P+8>2$

-8 -8

$5P>-6$

Divide both sides by 5.

$P>-\frac{6}{5}$

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Example of an irrational number that is less than 2 and greater than 1.5

disa [49]

For this case, the first thing you should do is take into account the irrational number definition.

An irrational number is one that can not be written as the quotient between two whole numbers.

Their number of decimals is unlimited and they are not periodic.

An irrational number within the specified domain is:

π/2 = 1.570796327

Answer:

an example of an irrational number that is less than 2 and greater than 1.5 is:

π/2 = 1.570796327

6 0

3 years ago

What is the absolute value of -3/5

prisoha [69]

Answer:

3/5

Step-by-step explanation:

absolute value is always positive

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2 years ago

Makayla is teaching Rodney how to construct a square inscribed in a circle. Makayla says Rodney should draw diameter AB, and the

Wewaii [24]

Answer:

c

Step-by-step explcanation:

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5 0

3 years ago

All about easy points here

RoseWind [281]

Answer:

90

Step-by-step explanation:

The formula for right triangular prisms is simple; 1/2 × a × b × c. So simply plug in your numbers (doesn't matter the order you plug in).

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5 0

3 years ago

Read 2 more answers

2x^2+3x-2, a=0 How do I find the derivative?

Ghella [55]

You can use the definition:

$\displaystyle f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}h$

Then if

$f(x) = 2x^2+3x-2$

we have

$f(x+h) = 2(x+h)^2+3(x+h) - 2 = 2x^2 + 4xh+2h^2+3x+3h-2$

Then the derivative is

$\displaystyle f'(x) = \lim_{h\to0}\frac{(2x^2+4xh+2h^2+3x+3h-2)-(2x^2+3x-2)}h \\\\ f'(x) = \lim_{h\to0}\frac{4xh+2h^2+3h}h \\\\ f'(x) = \lim_{h\to0}(4x+2h+3) = \boxed{4x+3}$

I'm guessing the second part of the question asks you to find the tangent line to <em>f(x)</em> at the point <em>a</em> = 0. The slope of the tangent line to this point is

$f'(0) = 4(0) + 3 = 3$

and when <em>a</em> = 0, we have <em>f(a)</em> = <em>f</em> (0) = -2, so the graph of <em>f(x)</em> passes through the point (0, -2).

Use the point-slope formula to get the equation of the tangent line:

<em>y</em> - (-2) = 3 (<em>x</em> - 0)

<em>y</em> + 2 = 3<em>x</em>

<em>y</em> = 3<em>x</em> - 2

5 0

3 years ago