Answer:
16.06 L was the initial volume of the balloon.
Explanation:
Initial moles of freon in ballon = ![n_1=9.79 mol](https://tex.z-dn.net/?f=n_1%3D9.79%20mol)
Initial volume of freon gas in ballon = ![V_1=?](https://tex.z-dn.net/?f=V_1%3D%3F)
Moles of freon gas added in the balloon = n = 3.50 mole
Final moles of freon in ballon = ![n_2=n_1+n=9.79 mol+3.50 mol=13.29 mol](https://tex.z-dn.net/?f=n_2%3Dn_1%2Bn%3D9.79%20mol%2B3.50%20mol%3D13.29%20mol)
Final volume of freon gas in ballon = ![V_2=21.8 L](https://tex.z-dn.net/?f=V_2%3D21.8%20L)
Using Avogadro's law:
( at constant pressure and temperature)
![V_1=\frac{V_2\times n_1}{n_2}=\frac{21.8 L\times 9.79 mol}{13.29 mol}=16.06L](https://tex.z-dn.net/?f=V_1%3D%5Cfrac%7BV_2%5Ctimes%20n_1%7D%7Bn_2%7D%3D%5Cfrac%7B21.8%20L%5Ctimes%209.79%20mol%7D%7B13.29%20mol%7D%3D16.06L)
16.06 L was the initial volume of the balloon.
Answer:
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Explanation:
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Organic chemistry as the the study of general properties and compositions of organic compounds.
<h3 />
<h3>What is organic chemistry?</h3>
Organic chemistry can be simply defined as the study of organic compounds.
Organic chemistry studies the structure, properties, composition, reactions, and preparation of carbon-containing compounds also known as organic compounds.
Thus, we can defined organic chemistry as the the study of general properties and compositions of organic compounds.
Learn more about organic chemistry here: brainly.com/question/704297
Answer: density equals 3 g/mL
Step by step explanation:
D=m/v
D=45/15
D=3
Answer:
![H^+(aq)+(ClO)^-(aq)\rightarrow HClO{(aq)}](https://tex.z-dn.net/?f=H%5E%2B%28aq%29%2B%28ClO%29%5E-%28aq%29%5Crightarrow%20HClO%7B%28aq%29%7D)
Explanation:
Hello there!
In this case, since perchloric acid is HClO4 and is a strong acid and calcium hypochlorite is Ca(ClO)2, the undergoing molecular chemical reaction turns out:
![2HClO_4{(aq)}+Ca(ClO)_2{(aq)}\rightarrow 2HClO{(aq)}+Ca(ClO_4)_2{(aq)}](https://tex.z-dn.net/?f=2HClO_4%7B%28aq%29%7D%2BCa%28ClO%29_2%7B%28aq%29%7D%5Crightarrow%202HClO%7B%28aq%29%7D%2BCa%28ClO_4%29_2%7B%28aq%29%7D)
Thus, since the resulting hypochlorous acid is weak, it does not fully ionize, so it remains unionized, however, we can write the ions for the other species:
![2H^++2(ClO_4)^-+Ca^{2+}+2(ClO)^-\rightarrow 2HClO{(aq)}+Ca^{2+}+2(ClO_4)^-](https://tex.z-dn.net/?f=2H%5E%2B%2B2%28ClO_4%29%5E-%2BCa%5E%7B2%2B%7D%2B2%28ClO%29%5E-%5Crightarrow%202HClO%7B%28aq%29%7D%2BCa%5E%7B2%2B%7D%2B2%28ClO_4%29%5E-)
Now, we can cancel out the spectator ions, calcium and perchlorate, to obtain:
![2H^+(aq)+2(ClO)^-(aq)\rightarrow 2HClO{(aq)}\\\\H^+(aq)+(ClO)^-(aq)\rightarrow HClO{(aq)}](https://tex.z-dn.net/?f=2H%5E%2B%28aq%29%2B2%28ClO%29%5E-%28aq%29%5Crightarrow%202HClO%7B%28aq%29%7D%5C%5C%5C%5CH%5E%2B%28aq%29%2B%28ClO%29%5E-%28aq%29%5Crightarrow%20HClO%7B%28aq%29%7D)
Best regards!