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3 years ago

Circle the letter of each chemical equation that is balanced

Chemistry

2 answers:

Dahasolnce [82]3 years ago

7 0

Just choice D.
If you find the number of atoms of each element, you will find that only choice D has the same amounts on each side of the equation.

Alenkasestr [34]3 years ago

5 0

Explanation:

3rd century fox news has been in the past year and it is a different person and you know what to do with a 3rd century fox news has been in the past year and it is a different person and you know what to do with a different person and you know what to do with a different person and you know what to do with a different person and you

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Which of the following is a change of state?

Step2247 [10]

Answer:

I think C. Hope this Helps!

Explanation:

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3 years ago

If 8.00 g NH4NO3 is dissolved in 1000 g of water, the water decreases in temperature from 21.00 degrees Celsius to 20.39 degrees

telo118 [61]

Answer:

25.7 kJ/mol

Explanation:

There are two heats involved.

heat of solution of NH₄NO₃ + heat from water = 0

q₁ + q₂ = 0

n = moles of NH₄NO₃ = 8.00 g NH₄NO₃ × 1 mol NH₄NO₃/80.0 g NH₄NO₃

∴ n = 0.100 mol NH₄NO₃

q₁ = n * ΔHsoln = 0.100 mol * ΔHsoln

m = mass of solution = 1000.0 g + 8.00 g = 1008.0 g

q₂ = mcΔT = 58.0 g × 4.184 J°C⁻¹ g⁻¹ × ((20.39-21)°C) = -2570.19 J

q₁ + q₂ = 0.100 mol ×ΔHsoln – 2570.19 J = 0

ΔHsoln = +2570.19 J /0.100 mol = +25702 J/mol = +25.7 kJ/mol

7 0

4 years ago

a chemist measured 75.00g of HCL into a volumetric flask and added water until the volume was 1.000 L. what is the molarity of t

Aleks04 [339]

Answer: M = 2.08 M

Explanation: Molarity is expressed as the number of moles per unit volume in liters. First convert the mass of HCl to moles using its molar mass. Then substitute the variables to the formula for molarity.

75.00 g HCl x 1 mole HCl / 36 g HCl

= 2.08 moles HCl

For Molarity.

M = n / L

= 2.08 moles HCl / 1.000 L

= 2.08 M

6 0

4 years ago

A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4

Harman [31]

Na₃PO₄ -----> 3Na(+) + PO₄(3-)
y-y.......................3y...........y

3y = 1.2
y = 0,4M

Na₃PO₄ -----> 3Na(+) + PO₄(3-)
0,4-0,4..............1,2..........0,4
0.........................1,2..........0,4

C = n/V
n = C×V
n = 0,4×0,65L
n = 0,26 mol Na₃PO₄

mNa₃PO₄: (23×3)+31+(16×4) = 164 g/mol

164g ----- 1 mol
Xg -------- 0,26 mol
X = 164×0,26
X = 42,64g Na₂SO₄

5 0

4 years ago

100 POINTS ANSWER FAST

andreev551 [17]

I would say b is the correct answer

6 0

3 years ago

Read 2 more answers