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saw5 [17]
3 years ago
12

Solve four and six eighths minus two and three fifths.

Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
5 0

Answer:

B

Step-by-step explanation:

maw [93]3 years ago
4 0

Answer:

I am not really sure but I asume it is C honestly I am sorry if I am wrong. But if I am right I really hope this helps

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Compare learning about functions to learning a new language. How are they similar
kow [346]

Answer: They are similar many ways.

Step-by-step explanation:

1. There is a law that guides both of them. Because each has a strick law.

2. They both need practice. Practice they say makes one perfect. When u practice both of them, you become familiar on how to use them.

3. The brain has to read meaning to either of the two to be able to be able to learn a pattern of learn.

4. Both language and functions are systems. They are made of different parts, language is made up of different words while function is made up of axioms which theorems.

7 0
4 years ago
Solve: <br>x + y = 7<br>3x - 2y = 11<br><br>By using Substituting method.​
Salsk061 [2.6K]

\large\underline{\sf{Solution-}}

\sf  \longmapsto x + y = 7 \: \: - - - (i)

\sf  \longmapsto 3x - 2y = 11 \: \: - - - (ii)

<u>By first equation,</u>

\sf  \longmapsto x + y = 7

\sf  \longmapsto x = 7 - y

<u>Now, we can find the original value of y.</u>

\sf \longmapsto 3x - 2y = 11

\sf  \longmapsto 3(7 - y) - 2y = 11

\sf  \longmapsto 21 - 3y - 2y = 11

\sf  \longmapsto 21 - 5y = 11

\sf  \longmapsto - 5y = 11 - 21

\sf  \longmapsto - 5y =  - 10

\sf  \longmapsto y = \dfrac{ - 10}{ - 5}

\sf  \longmapsto y = 2

<u>Now, we can find the original value of x.</u>

\sf  \longmapsto x + y = 7

\sf  \longmapsto x + 2 = 7

\sf  \longmapsto x = 7 - 2

\sf  \longmapsto x = 5

Therefore, the values of x and y are 5 and 2 respectively.

8 0
3 years ago
Read 2 more answers
Express 16³ + 12 × 16² + 10 as a hexadecimal number
ioda

Answer:

1c2a

Explain:

16^3 is 4096, and 16^2 is 256.

8 0
3 years ago
Need help asap!! first gets brainliest
Evgen [1.6K]

Answer:

-45

Step-by-step explanation:

Solve for x by simplifying both sides of the equation, then isolating the variable.

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3 years ago
Approximately 7.5 × 10^5 gallons of water flow over a waterfall each second. There are 8.6 × 10^4 seconds in one day. Approximat
tino4ka555 [31]

Answer:

6.45 \times  {10}^{10}

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3 years ago
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