Answer:
The range of angles is from 17.50° to 31.76°
Explanation:
The diffraction grid equation is as follows:
![dsen\theta=m\lambda](https://tex.z-dn.net/?f=dsen%5Ctheta%3Dm%5Clambda)
Clearing for ![\theta](https://tex.z-dn.net/?f=%5Ctheta)
![sen\theta=\frac{m\lambda}{d}](https://tex.z-dn.net/?f=sen%5Ctheta%3D%5Cfrac%7Bm%5Clambda%7D%7Bd%7D)
![\theta=sen^{-1}(\frac{m\lambda}{d})](https://tex.z-dn.net/?f=%5Ctheta%3Dsen%5E%7B-1%7D%28%5Cfrac%7Bm%5Clambda%7D%7Bd%7D%29)
where
is the angle,
is the order, in this case
,
is the wavelength, and
is defined as follows:
![d=\frac{1}{resolution}](https://tex.z-dn.net/?f=d%3D%5Cfrac%7B1%7D%7Bresolution%7D)
and since the resolution is 750 lines/mm wich is the same as ![750lines/1x10^{-3}m](https://tex.z-dn.net/?f=750lines%2F1x10%5E%7B-3%7Dm)
will be:
![d=\frac{1}{750lines/1x10^{-3}m}=\frac{1x10^{-3}m}{750lines}=1.33x10^{-6}m](https://tex.z-dn.net/?f=d%3D%5Cfrac%7B1%7D%7B750lines%2F1x10%5E%7B-3%7Dm%7D%3D%5Cfrac%7B1x10%5E%7B-3%7Dm%7D%7B750lines%7D%3D1.33x10%5E%7B-6%7Dm)
wich is the distance between each line of the diffraction grating.
substituting the values for
and
:
![\theta=sen^{-1}(\frac{(1)\lambda}{(1.33x10^{-6}m)})](https://tex.z-dn.net/?f=%5Ctheta%3Dsen%5E%7B-1%7D%28%5Cfrac%7B%281%29%5Clambda%7D%7B%281.33x10%5E%7B-6%7Dm%29%7D%29)
And we need to find two angle values: one for when the wavelength is 400nm and one for when it is 700 nm. So we will get the angle range
![\theta=sen^{-1}(\frac{(400x10^{-9})}{(1.33x10^{-6}m)})=17.50](https://tex.z-dn.net/?f=%5Ctheta%3Dsen%5E%7B-1%7D%28%5Cfrac%7B%28400x10%5E%7B-9%7D%29%7D%7B%281.33x10%5E%7B-6%7Dm%29%7D%29%3D17.50)
and
![\theta=sen^{-1}(\frac{(700x10^{-9})}{(1.33x10^{-6}m)})=31.76](https://tex.z-dn.net/?f=%5Ctheta%3Dsen%5E%7B-1%7D%28%5Cfrac%7B%28700x10%5E%7B-9%7D%29%7D%7B%281.33x10%5E%7B-6%7Dm%29%7D%29%3D31.76)
The range of angles is from 17.50° to 31.76°
Answer:
3.33 minutes (3 minutes and 20 seconds)
Explanation:
Speed of the runner = s = 5 m/s
We need to calculate how will it take for runner to complete 1 km. We have the speed, the distance and we need to find the time. Before performing any calculations, we must convert the values to same units.
Speed is in m/s and distance is in kilometers. So we have to either convert speed to km/s or distance into meters. In this case, converting distance into meters would be a convenient option.
1 kilo meters = 1000 meters
The distance, speed and time are related by the equation:
Distance = Speed x Time
So,
Time = Distance/Speed
Using the values, we get:
t = 1000/5
t = 200 seconds
This means, the runner can complete 1 kilometers in 200 seconds. Since, there are 60 seconds in a minute, we can convert this time to minutes, by dividing it by 60. i.e.
![200 \text{ sec} = \frac{200}{60} \text{ min} = 3.33 \text{ min}](https://tex.z-dn.net/?f=200%20%5Ctext%7B%20sec%7D%20%3D%20%5Cfrac%7B200%7D%7B60%7D%20%5Ctext%7B%20min%7D%20%3D%203.33%20%5Ctext%7B%20min%7D)
Thus, it will take the runner 3.33 minutes (3 minutes and 20 seconds) to travel 1 km.
The answer is 13.5 because 27÷3.0=13.5
Answer: If the force stays the same, the acceleration would decrease
Answer:
2(maximum), -2(minimum), -2(maximum).
Explanation:
V(t)= 2πcos πt--------------------------------------------------------------------------------(1).
Therefore, there is a need to integrate v(t) to get S(t).
S(t)= 2×sinπt + C ------------------------------------------------------------------------------(2).
Applying the condition given, we have s(0)= 0.
S(0)= 2sin ×π(0) + C.
Which means that; 0+C= 0. That is; C=0.
S(t)= 2 sin πt.
The mass moves to its highest positions at time,t=half(1/2=.5) and time,t=2.5.
Take note that; sin(π/2) = sin(5π/2) = 1 .
Also, the mass moves to its lowest position at time,t=(3/2); also, sin(3π/2) = -1.
Therefore, we have that 2 maximum; -2 minimum and -2 maximum.