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Misha Larkins [42]
3 years ago
9

The correct coefficients needed to balance the following reaction are:

Chemistry
1 answer:
velikii [3]3 years ago
5 0
I think the correct answer is c if not it’s d
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Z=3 1s2 express answer as an ion
sashaice [31]

Answer:

The element with electronic configuartion  1s² and atomic number 3 must be an cation.

Explanation:

The "Z" shows the atomic number. Z stand for zahl. It Is German word and meaning is " number".

In given question Z is equal to three which means an element with atomic number three.

Let consider the X is an element with atomic number three having electronic configuration 1s², but according to this atomic number there should be one more electron present is 2s. If X has the electronic configuration 1s² it means that it lose one electron and X is present in the form of cation.

X⁺ =  1s²

7 0
3 years ago
A compound with the empirical formula ch2 has a molar mass of 98 g/mol what is the molecular formula for this compound ?
madam [21]
Approximate molecular masses:
Molecular mass of C = 12
Molecular mass of H = 1

Let n = moles required for CH₂.
Then
nCH₂ = 98
n(12 + 2*1) = 98
14n = 98
n = 7

Answer: The molecular formula is 7CH₂

7 0
3 years ago
NEED HELP ASAP!!!<br> Please choose correctly!!<br><br> Will mark brainliest thank you!!!
almond37 [142]
You will have a excess gas
4 0
3 years ago
Edith's checkerspot is a species of butterfly that lives along the west coast of North America. In recent years, scientists have
Gelneren [198K]

........ . ................

6 0
3 years ago
Gold forms a substitutional solid solution with silver. Compute the number of gold atoms per cubic centimeter for a silver-gold
Sonja [21]

Answer:

The Number of gold atoms are =N_{Au}=1.81718*10^{22}\ atoms/cm^3

Explanation:

The formula we are going to use is:

N_{Au}=\frac{N_A*C_{Au}}{{\frac{C_{Au}A_{Au} }{\rho_{Au}}}+\frac{A_{Au}}{\rho_{Ag}}(100-C_{Au})}

Where:

N_{Au} are number of gold atoms.

N_A is Avogadro Number.

C_{Au} is the amount of gold.

A_{Au} is the atomic weight of gold.

\rho_{Au} is the density of gold.

\rho_{Ag} is the density of silver.

C_{Ag} is the amount of silver.

N_{Au}=\frac{6.023*10^{23}*45\%wt}{\frac{45\%wt*196.97}{19.32}+\frac{196.97}{10.49}(100-45\%wt)}\\ N_{Au}=1.81718*10^{22}\ atoms/cm^3

The Number of gold atoms are =N_{Au}=1.81718*10^{22}\ atoms/cm^3

5 0
4 years ago
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