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Minchanka [31]
3 years ago
9

SCIENCE HW PLEASE HELP ASAP

Chemistry
1 answer:
SIZIF [17.4K]3 years ago
7 0

Answer:

I’m pretty sure the answer is blind spot one or the actual distance of traffic I’ll asume actually distance traffic

Explanation:

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20.0g of H2(g) and 32g of O2(g) are reacted produce H2O(l). The amount of hydrogen left behind after completion of reaction is?
Hitman42 [59]

Answer:

8 moles = 16 gm of H2 left over

Explanation:

The balanced equation is

2 H2  +  O2   ===> 2 H2 O

20 g H2   =    20 g / 2 gm/mole = 10 moles of H2

32 g O2   =    32g / 32 g / mole = 1 mole O2

From the balanced equation, you can see each 2 moles of H2 requires 1 Mole of O2

  you would need 20 moles of O 2 to react withe the 10 moles of H2

      but you only have 1 mole of O2      so   8 moles of H2 will be left

5 0
2 years ago
A solution of 34% nacl is separated by a semipermeable membrane to a solution of 22% glucose. the membrane is only permeable to
Katyanochek1 [597]
The net osmosis will occur in the direction of the NaCl solution. This is because the solute concentration on that side is greater than that of the glucose solution. Osmosis is the process by which liquids move through semi permeable membrane from the region of lower concentration to the region of higher concentration.
Thus the water is going to move from the glucose solution into the NaCl solution.<span />
7 0
4 years ago
Read 2 more answers
Por qué razón se fomenta la inmigración Europea?​
Morgarella [4.7K]

Hola aquí va la respuesta!

Se fomentó la inmigración europea porque la economía no era buena y vinieron a Paraguay para mejorar su situación.

8 0
3 years ago
Read 2 more answers
How many grams of argon would it take to fill a large light bulb with a volume of 0.745 L at STP?
EastWind [94]

Answer:

Mass = 1.33 g

Explanation:

Given data:

Mass of argon required = ?

Volume of bulb = 0.745 L

Temperature and pressure = standard

Solution:

We will calculate the number of moles of argon first.

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

By putting values,

1 atm ×0.745 L = n × 0.0821 atm.L/mol.K× 273.15 K

0.745 atm. L = n × 22.43 atm.L/mol

n = 0.745 atm. L / 22.43 atm.L/mol

n = 0.0332 mol

Mass of argon:

Mass = number of moles × molar mass

Mass = 0.0332 mol × 39.95 g/mol

Mass = 1.33 g

8 0
3 years ago
PLEASE ANSWEER THIS HURRY HURRRRRRRRRYY
klemol [59]
The first one would be it
6 0
4 years ago
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