Answer:
Chlorine is more reactive than bromine because the chlorine atom has fewer shells and the electronic bonding is much stronger. The electrons are closer to the nucleus, therefore it is easier for chlorine to attract and hold electrons in its outer shell forming stronger bonds with other atoms.
(As you go down Group 7/the Halogens - they get less reactive)
<span>4.3065 g
First, lookup the atomic weights of all the elements involved.
Atomic weight of Calcium = 40.078
Atomic weight of Carbon = 12.0107
Atomic weight of Hydrogen = 1.00794
Atomic weight of Oxygen = 15.999
Atomic weight of Sulfur = 32.065
Now calculate the molar masses of the reactants and product
Molar mass H2SO4 = 2 * 1.00794 + 32.065 + 4 * 15.999
= 98.07688 g/mol
Molar mass CaCO3 = 40.078 + 12.0107 + 3 * 15.999
= 100.0857 g/mol
Molar mass CaSO4 = 40.078 + 32.065 + 4 * 15.999
= 136.139 g/mol
The balanced reaction for H2SO4 with CaCO3 is
CaCO3 + H2SO4 ==> CaSO4 + H2O + CO2
So it takes 1 mole each of CaCO3 and H2SO4 to produce 1 mole of CaSO4. Let's see how many moles of CaCO3 and H2SO4 we have.
CaCO3: 3.1660 g / 100.0857 g/mol = 0.031632891 mol
H2SO4: 3.2900g / 98.07688 g/mol = 0.033545113 mol
We have a slight excess of H2SO4, so the amount of CaCO3 is the limiting reactant and we should have 0.031632891 moles of product. To determine its mass, multiply the number of moles by the molar mass computed earlier.
0.031632891 mol * 136.139 g/mol = 4.306470148 g
Since we have 5 significant figures in our data, round the result to 5 figures, giving 4.3065 g</span>
1) The forward reaction is N2 (g) + O2 (g) → 2NO
(that reaction requires special contitions because at normal pressures and temperatures N2 and O2 do not react to form another compound.
2) The equiblibrium equation is
N2 (g) + O2 (g) ⇄ 2NO
3) Then, the reverse reaction is
2NO → N2(g) + O2(g)
Answer: 2NO → N2(g) + O2(g)
Answer:
0.2M H2C6H5O7 < 0.2M H2C2O4
Explanation:
A weak acid/base ionizes to a very small extent in water. Hence, if we say that a substance is a weak acid/base, its percentage of ionization in solution is very little.
More volume of a very weak acid is required to neutralize a strong base. Since NaOH is a strong base, the weaker acid among the duo will require more volume for neutralization.
Since H2C6H5O7 is a weaker acid than H2C2O4, equal concentration of the both acids will require less volume of H2C2O4 than H2C6H5O7 to neutralize 0.50 M NaOH.
Answer:
It dissolves into the water
Na₂SO₄ + H₂O → 2Na₊_{aq} + SO₄²-_{aq}
Hope this helps :)
Have a great day !
5INGH
Explanation: