Answer:
1. Mass of KCl produced = 774.8 g of KCl
2. Mass of KNO₃ produced = 13.837g
3. Moles of NaOH made = 0.846 moles
4. Moles of LiCl produced = 0.846 moles
5. Moles of CO₂ produced = 207.6 moles
Explanation:
1. From the equation of reaction, 1 mole of ZnCl₂ produces, 2 moles of KCl.
5.02 moles of ZnCl₂ will produce, 2 × 5.02 moles of KCl = 10.4 moles of KCl
Molar mass of KCl = (39 + 35.5) g/mol = 74.5 g/mol
10.4 moles of KCl = 10.4 × 74.5 g
Mass of KCl produced = 774.8 g of KCl
2. Mole ratio of KNO₃ and KOH = 1:1
O.137 moles of KOH will produce 0.137 moles of KNO₃
Molar mass of KNO₃ = 101 g/mol
Mass of KNO₃ produced = 0.137 × 101 g = 13.837g
3. Molar mas of Ca(OH)₂ = 74.0 g
Moles of Ca(OH)₂ in 31.3 g = 31.3/74.0 = 0.423 moles of Ca(OH)₂
Mole ratio of NaOH and Ca(OH)₂ in the reaction = 2 : 1
Moles of NaOH made = 2 × 0.423 = 0.846 moles
4. Molar mass of MgCl₂ = 95.0 g
Moles of MgCl₂ in 40.2 g = 40.2/95.0 = 0.423 moles
From the reaction equation, mole ratio of MgCl₂ and LiCl = 1:2
Moles of LiCl produced = 2 × 0.423 = 0.846 moles
5. From the equation of reaction, 1 mole of C₆H₁₀O₅ produces 6 moles of cO₂
34.6 moles of C₆H₁₀O₅ will produce 34.6 × 6 moles of CO₂
Moles of CO₂ produced = 207.6 moles
