The product of this reaction is a halohydrin as shown here.
<h3>What are the products?</h3>
We have a reaction that first involves the formation an alkene as the bases are used on the first substrate. The alkene that is thus created is now able to react with the bromine in water.
The first step of the reaction is where the multiple bond is created and this multiple bond is what can now go on to participate in a chemical reaction in the next step of the process of reaction as shown in the image.
Bromine in water is also hat we call bromine water. This bromine water is able to add across a double bond and when that happen we will have a saturated compound. This could also be regarded as halohydrin reaction.
Recall that the first step of the reaction of the alkene with bromine is the formation of a dibromide via the brominium intermediate. This is now followed by reaction with water to form the halohydrin product.
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Answer:
The Rutherford Model shows an atom with electrons orbiting a fixed, positively charged nucleus in set, predictable paths. The Bohr model shows electrons travel in defined circular orbits around the nucleus.
50 percent
there are 8 atoms in this molecule
and 4 of them are oxygen molc. so:

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<h3>
Answer:</h3>
3.6 × 10^24 molecules
<h3>
Explanation:</h3>
Concept: Moles and Avogadro's number
- We need to know that one mole of a compound has molecules equivalent to the Avogadro's number, 6.022 × 10^23.
- Therefore; 1 mole of a compound contains 6.022 × 10^23 molecules
In this case;
We are given 6 moles of Methane;
But 1 mole of methane = 6.022 × 10^23 molecules
Therefore;
Molecules = Number of moles × Avogadro's number
= 6 moles × 6.022 × 10^23 molecules/mole
= 3.613 × 10^24 molecules
= 3.6× 10^24 molecules
Thus, there are 3.6× 10^24 molecules in 6 moles of methane.