1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kupik [55]
2 years ago
11

How many liters are in a 0.115 M solution containing 1.55 moles of dissolved KBr?

Chemistry
1 answer:
Anika [276]2 years ago
5 0
13.48 is your answer.

M=moles/liters we have M=.115 and moles=1.55

Input those values into the equation
.115=1.55/L

Solve for L
1.55/.115=13.48
You might be interested in
Howtocalculatethevolumeofcarbondioxideproducedwhen400gofmarblewereats.t.p<br>​
lys-0071 [83]

Answer:

so 0.15 moles X 22.4 dm3/mole=3.36 dm3. Next we find the moles of hexane combusted, and then the moles of CO2. Finally, we find the volume of CO2 using the fact that at STP, 1 mole of gas = 22.4 dm3.

3 0
3 years ago
What is the total energy change for the following reaction:CO+H2O-CO2+H2
Alekssandra [29.7K]

Answer:

\large \boxed{\text{-41.2 kJ/mol}}

Explanation:

Balanced equation:    CO(g) + H₂O(g) ⟶ CO₂(g) + H₂(g)

We can calculate the enthalpy change of a reaction by using the enthalpies of formation of reactants and products

\Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)

(a) Enthalpies of formation of reactants and products

\begin{array}{cc}\textbf{Substance} & \textbf{$\Delta_{\text{f}}$H/(kJ/mol}) \\\text{CO(g)} & -110.5 \\\text{H$_{2}$O} & -241.8\\\text{CO$_{2}$(g)} & -393.5 \\\text{H$_{2}$(g)} & 0 \\\end{array}

(b) Total enthalpies of reactants and products

\begin{array}{ccr}\textbf{Substance} & \textbf{Contribution)/(kJ/mol})&\textbf{Sum} \\\text{CO(g)} & -110.5& -110.5 \\\text{H$_{2}$O(g)} &-241.8& -241.8\\\textbf{Total}&\textbf{for reactants} &\mathbf{ -352.3}\\&&\\\text{CO}_{2}(g) & -393.5&-393.5 \\\text{H}_{2} & 0 & 0\\\textbf{Total}&\textbf{for products} & \mathbf{-393.5}\end{array}

(c) Enthalpy of reaction \Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)= \text{-393.5 kJ/mol - (-352.3 kJ/mol}\\= \text{-393.5 kJ/mol + 352.3 kJ/mol} = \textbf{-41.2 kJ/mol}\\ \text{The total enthalpy change is $\large \boxed{\textbf{-41.2 kJ/mol}}$}

4 0
3 years ago
Why is it important to start at the zero mark of a ruler/meterstick + triple beam balance when making measurements?
sergeinik [125]
Because if you start at one for example you starting at a extra cm/m/mm. So when you get your measurement result it will be wrong by just one cm/m/mm. Hope this wasn't too confusing.
3 0
3 years ago
What are giant piles of mining waste called?
weqwewe [10]
The giant piles of mining waste called tailings. These wastes consists of ground rock and process effluents from a mining plant. These wastes are stored on a surface either in a facility or in the form of piles. Also, sometimes it is stored underground in areas that are mined out.
3 0
3 years ago
Read 2 more answers
In an experiment, two unknown compounds (one an ether and the other an amine) of equal molecular mass were dissolved in water. T
Fittoniya [83]

Answer:

It is an amine; it contains a nitrogen atom that will allow nitrogen-hydrogen bonds to form while in water.

Explanation:

The solubility of amines owes largely to the electronegativity difference between nitrogen and hydrogen. Remember that when hydrogen is bonded to highly electronegative element such as nitrogen, intermolecular hydrogen bonding is possible with water molecules. This explains the greater solubility of amines in water.

Ether molecules do have an oxygen atom, however, and engage in hydrogen bonding with water molecules to a lesser extent compared to amines.

Also, amines participate in some acid-base reactions that lead to the formation of diethylammonium hydroxide, an ion which leads to a greater solubility of amines compared to an ether.

Hence, compound A is an amine.

3 0
3 years ago
Other questions:
  • A chemist adds 405.0mL of a 0.79M sodium carbonate solution to a reaction flask. Calculate the millimoles of sodium carbonate th
    13·1 answer
  • What is the molarity of NaOH solution if 30.0g of NaOH solid was dissolved in 500.ml of water? (molar mass of NaOH is 40.0 g/mol
    6·1 answer
  • How are a mole and a dozen similar​
    12·1 answer
  • Is Fe + S a mixture, compound, or element?
    5·1 answer
  • 14.7 grams of magnesium reacts completely with 9.7 grams of oxygen to form magnesium oxide (MgO). What is the percent compositio
    13·1 answer
  • What is the systematic name of the following compound?
    5·1 answer
  • Heyoo I need help pleaseeeeee​
    5·2 answers
  • The periodic table... old help me is a test..​
    14·1 answer
  • Anyone available to be a learning partner?​
    12·1 answer
  • If the universe is expanding but the expansion is slowing down, what will the eventual
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!