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Sveta_85 [38]
4 years ago
5

Write an investigative question

Chemistry
1 answer:
pshichka [43]4 years ago
6 0

Answer:

What happened?

What was the date, time and duration of the incident or behavior?

How many times did this happen?

Where did it happen?

How did it happen?

Did anyone else see it happen? Who? What did they say? What did they do?

Was there physical contact? Describe it. Demonstrate it.

What did you do in response to the incident or behavior?

What did you say in response to the incident or behavior?

How did the subject of the allegation react to your response?

Did you report this to anyone in management? To whom? When? What they say and/or do?

Did you tell anyone about the incident or behavior? Who? What did they say and/or do?

Do you know whether the subject of the allegation has been involved in any other incidents?

Do you know why the incident or behavior occurred?

Do you know anyone else who can shed light on this incident?

Is there anything else you want to tell me that I haven’t asked you?

Explanation:

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Answer:

1st = saturated

Explanation:

Bro first ka answer saturated he

4 0
2 years ago
Scientists group similar organisms together through a process called …..
Bond [772]

Answer:

plz i need to ask another question i hope u understand

Explanation:

4 0
3 years ago
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What else is produced when sodium carbonate decomposes? Na2CO3 Na2O +
andriy [413]

When a single compound breaks down into two or more compounds or elements in a chemical reaction then it is known as decomposition reaction.

The chemical symbol for sodium carbonate is Na_2CO_3.

The decomposition of sodium carbonate is:

Na_2CO_3\rightarrow Na_2O+ CO_2

The decomposition of sodium bicarbonate, Na_2CO_3 will result in the formation of sodium oxide, Na_2O and carbon dioxide, CO_2.

Hence, carbon dioxide, CO_2 will produce with sodium oxide, Na_2O on decomposition of Na_2CO_3.

7 0
3 years ago
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A student is preparing to perform a series of calorimetry experiments. She first wishes to determine the calorimeter constant (C
laila [671]

Answer:

  • First choice: 99 J/K

Explanation:

<u>1) First law of thermodynamic (energy balance)</u>

  • Heat released by the the hot water (345K ) = Heat absorbedby the cold water (298 K) + Heat absorbed by the calorimeter

<u>2) Energy change of each substance:</u>

  • General formula:

     

Heat released or absorbed = mass × Specific heat × change in temperature

  • density of water: you may take 0.997 g/ ml as an average density for the water.

  • mass of water: mass = density × volume = 50.0 ml × 0.997 g/ml = 49.9 g

  • Specif heat of water: 1 cal / g°C

  • Heat released by the hot water:

       Heat₁ = 49.9 g × 1 cal / g°C × (345 K - 317 K) = 49.9 g × 1 cal / g°C × (28K)

  • Heat absorbed by the cold water:

       Heat₂ = 49.9 g × 1 cal / g°C × (317 K - 298 K) = 49.9 g × 1 cal / g°C × (19K)

  • Heat absorbed by the calorimeter

       Heat₃ = Ccal × (317 K - 298 K) = Ccal × (19K)

<u>4) Balance</u>

  • Heat₁ = Heat₂ + Heat₃

49.9 g × 1 cal / g°C × (28 K) = 49.9 g × 1 cal / g°C × (19 K) + Ccal × (19 K)

  • Solve for Ccal

Ccal = [49.9 g × 1 cal / g°C × (28 K) - 49.9 g × 1 cal / g°C × (19 K) ] / 19K

Ccal = 23.6 cal/ K

  • Convert to cal / K to Joule / K

  • 1 cal = 4.18 Joule

       23.6 cal / K × 4.18 J / cal = 98.6 J/K

Which rounded to 2 signficant figures leads to 99 J/k, which is the first choice.

4 0
4 years ago
How does the energy of an electron close to the nucleus compare to the energy of electrons farther away from the nucleus?
S_A_V [24]
The electrons closer to the nucleus would have more energy than the electrons farther away from the nucleus.
6 0
3 years ago
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