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4 years ago

Write an investigative question

Chemistry

1 answer:

pshichka [43]4 years ago

6 0

Answer:

What happened?

What was the date, time and duration of the incident or behavior?

How many times did this happen?

Where did it happen?

How did it happen?

Did anyone else see it happen? Who? What did they say? What did they do?

Was there physical contact? Describe it. Demonstrate it.

What did you do in response to the incident or behavior?

What did you say in response to the incident or behavior?

How did the subject of the allegation react to your response?

Did you report this to anyone in management? To whom? When? What they say and/or do?

Did you tell anyone about the incident or behavior? Who? What did they say and/or do?

Do you know whether the subject of the allegation has been involved in any other incidents?

Do you know why the incident or behavior occurred?

Do you know anyone else who can shed light on this incident?

Is there anything else you want to tell me that I haven’t asked you?

Explanation:

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The formula for mole fraction is:

$mole fraction of solute = \frac{number of moles of solute}{total number of moles of solution}$ -(1)

The solubility of oxygen gas = 1.0 mmol/L (given)

1.0 mmol/L means 1.0 mmol are present in 1 L.

Converting mmol to mol:

$1.00 mmol\times \frac{1 mol}{1000 mmol} = 0.001 mol$

So, moles of oxygen = 0.001 mol

For moles of water:

1 L of water = 1000 mL of water

Since, the density of water is 1.0 g/mL.

$Density = \frac{mass}{volume}$

$Mass = 1.0 g/ml\times 1000 mL = 1000 g$

So, the mass of water is 1000 g.

Molar mass of water = 18 g/mol.

Number of moles of water = $\frac{1000 g}{18 g/mol} = 55.55 mol$

Substituting the values in formula (1):

$mole fraction = \frac{0.001}{55.55+0.001}$

$mole fraction = 1.8\times 10^{-5}$

Hence, the mole fraction is $1.8\times 10^{-5}$ .

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Answer:

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