Answer:
A linear pattern is a continuous decrease or increase in numbers over time. On a graph, this data appears as a straight line angled diagonally up or down (the angle may be steep or shallow). So the trend either can be upward or downward.
Explanation:
Answer:
(i) specific heat
(ii) latent heat of vaporization
(iii) latent heat of fusion
Explanation:
i. Q = mcΔT; identify c.
Here, Q is heat, m is the mass, c is the specific heat and ΔT is the change in temperature.
The amount of heat required to raise the temperature of substance of mass 1 kg by 1 degree C is known as the specific heat.
ii. Q = mLvapor; identify Lvapor
Here, Q is the heat, m is the mass and L is the latent heat of vaporization.
The amount of heat required to convert the 1 kg liquid into 1 kg vapor at constant temperature.
iii. Q = mLfusion; identify Lfusion
Here, Q is the heat, m is the mass and L is the latent heat of fusion.
Here, Q is the heat, m is the mass and L is the latent heat of vaporization.
The amount of heat required to convert the 1 kg solid into 1 kg liquid at constant temperature.
Answer:
51.69 g of Fe
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2Fe + 3S —> Fe₂S₃
Next, we shall determine the mass of Fe that reacted and the mass of Fe₂S₃ produced from the balanced equation. This can be obtained as follow:
Molar mass of Fe = 56 g/mol
Mass of Fe from the balanced equation = 2 × 56 = 112 g
Molar mass of Fe₂S₃ = (2×56) + (3×32)
= 112 + 96
= 208 g/mol
Mass of Fe₂S₃ from the balanced equation = 1 × 208 = 208 g
SUMMARY:
From the balanced equation above,
112 g of Fe reacted to produce 208 g of Fe₂S₃.
Finally, we shall determine the mass of Fe needed to produce 96 g of Fe₂S₃. This can be obtained as follow:
From the balanced equation above,
112 g of Fe reacted to produce 208 g of Fe₂S₃.
Therefore, Xg of Fe will react to produce 96 g of Fe₂S₃ i.e
Xg of Fe = (112 × 96)/208
Xg of Fe = 51.69 g
Thus, 51.69 g of Fe is needed for the reaction.
The standard enthalpy of formation for chlorine is zero but the standard entropy is larger than 0 because it is the elemental state of chlorine.
The standard enthalpy of formation for chlorine is zero because cl2 is the elemental state of chlorine and it does not require any energy for the formation of the standard state of chlorine.
The entropy of any system cannot be negative. It can only be positive or zero.
The entropy of a system will become zero only at a absolute zero temperature.
That's why the entropy of chlorine in elemental state is more than zero because absolutely zero temperature can't be obtained.
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