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mrs_skeptik [129]
3 years ago
8

Which of the following is not a true statement?

Mathematics
1 answer:
Elan Coil [88]3 years ago
5 0

Answer:

C.

Step-by-step explanation:

A. -12 = -12

b. -2 = -2

C -4 = -8

D. -4 = -4

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Daniel sold his washing machine for $829. He orignally paid $975 for it. What is Daniel's percentage loss?
Lynna [10]
Aproximately 15%

975-829=146 (difference)
(146/975)×100 = 14.974435897
7 0
3 years ago
Jack's family went out to dinner at a diner. The total bill was $78.99. The
puteri [66]

Answer:

The tax was 5.13

Step-by-step explanation:

Take the amount and multiply by the tax rate

78.99 * 6.5 %

Change to a decimal

78.99 * .065

Round to the nearest cent

5.13

6 0
3 years ago
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ABCDE is a regular pentagon. The apothem is 9.7 cm, and AB = 14.1 cm. Calculate the area of the pentagon. Round the answer to th
devlian [24]
        ABCDE is a regular pentagon which consists of 5 equal triangles.
Area of the pentagon ABCDE:
        A = 5 * 1.41 * 9.7 / 2 = 683.85 / 2 = 341.925 ≈ 341.9 cm²
       Answer: The area of the pentagon ABCDE is 341.9 cm².
8 0
3 years ago
Use this system of equations to answer the questions
Over [174]

Answer:

1. To eliminate x-term, multiply the second by -2

2. To eliminate y-term, multiply the second by 3

Step-by-step explanation:

4x - 9y = 7 (1)

-2x + 3y = 4 (2)

1. To eliminate x-term, multiply the second by -2

-2x + 3y = 4 (2) × 2

-4x + 6y = 8 (3)

4x - 9y = 7 (1)

Add (3) and (1)

6y - 9y = 8 + 7

-3y = 15

y = 15/-3

y = -5

4x - 9y = 7 (1)

4x - 9(-5) = 7

4x + 45 = 7

4x = 7 - 45

4x = -38

x = -38/4

x = -9.5

4x - 9y = 7 (1)

-2x + 3y = 4 (2)

2. To eliminate y-term, multiply the second by 3

-2x + 3y = 4 (2) × 3

-6x + 9y = 12 (3)

4x - 9y = 7 (1)

-6x + 4x = 12 + 7

-2x = 19

x = 19/-2

x = -9.5

4x - 9y = 7 (1)

4(-9.5) - 9y = 7

-38 - 9y = 7

-38 - 7 = 9y

-45 = 9y

y = -45/9

y = -5

6 0
2 years ago
Read 2 more answers
WILL MARK BRAINLIEST ASAP!!
7nadin3 [17]

\dfrac{x^2+ax-4}{x+2}+\dfrac{x+b}{x+2}=\dfrac{x^2+ax-4+x+b}{x+2}=\dfrac{x^2+(a+1)x+(b-4)}{x+2}\\\\\dfrac{x^2+(a+1)x+(b-4)}{x+2}=x+1\\\\\dfrac{x^2+(a+1)x+(b-4)}{x+2}=\dfrac{(x+1)(x+2)}{x+2}\\\\\dfrac{x^2+(a+1)x+(b-4)}{x+2}=\dfrac{(x)(x)+(x)(2)+(1)(x)+(1)(2)}{x+2}\\\\\dfrac{x^2+(a+1)x+(b-4)}{x+2}=\dfrac{x^2+2x+x+2}{x+2}\\\\\dfrac{x^2+(a+1)x+(b-4)}{x+2}=\dfrac{x^2+3x+2}{x+2}\iff a+1=3\ \wedge\ b-4=2\\\\\boxed{a=2\ \wedge\ b=6}

3 0
3 years ago
Read 2 more answers
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