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konstantin123 [22]
3 years ago
9

PLEASE HELP (100)

Physics
1 answer:
morpeh [17]3 years ago
3 0

Answer:

The work done will be W=55.27\: J

Explanation:

The work equation is given by:

W=F\cdot x

Where:

F is the force due to gravity (weight = mg)

x is the length of the ramp (3 m)

Now, the force acting here is the component of weight in the ramp direction, so it will be:

F_{x-direction}=mgsin(28)

Therefore, the work done will be:

W=mgsin(28)*3

W=4*9.81*sin(28)*3

W=55.27\: J

I hope it helps you!

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6 0
3 years ago
A Hooke's law bowstring is stretched x meters until a force of f newtons is applied, and then held. By what factor will the elas
Liono4ka [1.6K]

The elastic potential energy increases by a factor of 9

Explanation:

The elastic potential energy of a bowstring is given by

E=\frac{1}{2}kx^2 (1)

where

k is the spring constant

x is the elongation of the bowstring

Hooke's law states the relationship between the force applied and the elongation of an elastic object:

F=kx

where

F is the force applied

x is the elongation

We can rewrite it as

x=\frac{F}{k}

And substituting into (1),

E=\frac{1}{2}k(\frac{F}{k})^2=\frac{F^2}{2k}

In  this problem, the force applied to the bowstring is tripled,

F' = 3F

So the final elastic potential energy is:

E'=\frac{(3F)^2}{2k}=9(\frac{F^2}{2k})=9E

So, the elastic potential energy increases by a factor of 9.

Learn more about potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

7 0
3 years ago
During a certain time interval, the angular position of a swinging door is described by θ = 4.91 + 9.7t + 2.06t2, where θ is in
polet [3.4K]

Explanation:

a)

θ = 4.91 + 9.7t + 2.06t² when t = 0

θ = 4.91 rad

θ = 4.91 + 9.7t + 2.06t²

ω = dθ/dt = 9.7 + 2.06t, when t =0

ω = dθ/dt = 9.7 + 0

ω = 9.7 rad/s

α = d²θ/dt² = 2.06

α= 2.06 rad/s²

b) please use same method above for t = 2.94 s

3 0
4 years ago
What is the resultant displacement of the two vectors below
NeX [460]

Answer:

The resultant displacement is 5.8 cm, 31° South of the West axis ⇒ 4th

answer

Explanation:

<u><em>A resultant vector</em></u> is the combination of two or more single vectors

If the two vectors are perpendicular, then

<em><u>The magnitude</u></em> of the resultant vector = \sqrt{x^{2}+y^{2}},where

x represents the horizontal vector and y represents the vertical vector

<em><u>The direction</u></em> of the resultant vector is tan^{-1}\alpha, where α

is the angle between the horizontal vector and the resultant vector

Vector 1 is 5 cm due to West-axis

Vector 2 is 3 cm due to South-axis

We need to find the resultant displacement of them

The West and South are perpendicular

The West is the horizontal vector and South is the vertical vector

The magnitude of the resultant displacement s is:

s=\sqrt{(5)^{2}+(3)^{2}}

s=\sqrt{25+9}

s=\sqrt{34}=5.8

The direction of the resultant displacement s is:

tan^{-1}\frac{3}{5}=31° south of the west (between the west and

the resultant displacement)

<em>The resultant displacement is 5.8 cm, 31° South of the West axis</em>

6 0
3 years ago
An object is placed 10 cm from a convex lens of focal length 20 cm. What is the lateral magnification of the object?.
Airida [17]

Answer:Solution

verified

Verified by Toppr

Given:u=−10cm               f=20cm        (convex lens)

To find: v and image's nature.

Solution: From lens formula

v

1

​

−

u

1

​

=

f

1

​

v

1

​

+

10

1

​

=

20

1

​

Explanation:

7 0
2 years ago
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