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konstantin123 [22]
3 years ago
9

PLEASE HELP (100)

Physics
1 answer:
morpeh [17]3 years ago
3 0

Answer:

The work done will be W=55.27\: J

Explanation:

The work equation is given by:

W=F\cdot x

Where:

F is the force due to gravity (weight = mg)

x is the length of the ramp (3 m)

Now, the force acting here is the component of weight in the ramp direction, so it will be:

F_{x-direction}=mgsin(28)

Therefore, the work done will be:

W=mgsin(28)*3

W=4*9.81*sin(28)*3

W=55.27\: J

I hope it helps you!

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A light ray moving from oil (n=1.38) into an unknown material. If the light is incident at 35 and refracts at 23, what is the in
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<h3>Snell's law</h3>

index of refraction (n) = Sine i / Sine r

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<h3>How to determine the refractive index </h3>

From the question given above, the following data were obtained:

  • Index of refraction of oil (nₒ) = 1.38
  • Angle of incidence (i) = 35°
  • Angle of refraction (r) = 23°
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nₒSine i = nᵣSine r

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Learn more about Snell's law:

brainly.com/question/25758484

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