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Umnica [9.8K]
3 years ago
15

Measurements of acceleration are given in units of ?

Physics
2 answers:
kaheart [24]3 years ago
6 0
The measurement of acceleration are meters per a second
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Lady_Fox [76]3 years ago
3 0
Meters per second squared: \frac{m}{s^{2}}

If you think about it, acceleration is about how fast speed changes. Speed is measured in meters per second: \frac{m}{s}

So if you take that and just measure it over time, you get meters per second squared.
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Can anybody help me please?
vovangra [49]

Answer:

1,2,5

Explanation:

7 0
2 years ago
Gold has a higher density than tin? True or false
Ganezh [65]

Answer:

True. Gold does have a higher density than tin

3 0
3 years ago
A 4.04 kg block slides down a smooth, frictionless plane having an inclination of 30◦. The acceleration of gravity is 9.8 m/s^2.
aleksandrvk [35]

Answer:

Explanation:

What a lot of words to solve such a simple problem! The perpendicular force is the one that is pushing straight down on the plane. There is no side to side movement here or friction acting on this dimension at all. Perpendicular force is the same as the weight of the block. That's it! Perpendicular force is also normal force which is the same thing as weight:

w = mg so

w = (4.04)(9.8) and

w = 4.0 × 10¹ N

5 0
3 years ago
If the volume of one drop is 0.031 mL according to Stu Dent’s measurement, approximately what volume would 22 drops be? Answer w
olasank [31]

Answer:

Volume of 22 drop will be 0.68 ml

Explanation:

We have given volume of one drop = 0.031 ml

We know that 1 liter = 1000 ml

So 1ml=10^{-3}L

So 0.031 ml will be equal to 0.031\times 10^{-3}L

We have to find the volume of 22 drop

For finding volume of 22 drop we have to multiply volume of one drop by 22

So volume of 22 drop will be =22\times 0.031\times 10^{-3}=0.682\times 10^{-3}L=0.68mL

So volume of 22 drop will be 0.68 ml

7 0
3 years ago
A platinum wire is used to determine the melting point of indium. The resistance of the platinum wire is 2.000 Ω at 20°C and inc
Molodets [167]

Answer:

The melting point of indium is 157.436 degrees Celsius.

Explanation:

The resistance of the platinum wire, R1 = 2

The temperature at R1 is, T1 = 20 degrees Celsius.

The increased resistance, R2 = 3.072

Let the temperature at 3.072 = T2

Now find the temperature at which the indium starts melting.

We know that α = ( R2 - R1 ) / [ R1 × ( T2 - T1 ) ]

Given, α = 3.9 x 10^-3/ degrees Celsius.

T2- T1   = ( R2 - R1 ) / R1 α

T2 – T1 = (3.072 – 2) / (2 × 3.9 x 10^-3)

T2 – T1 = 137.436

T2 = T1 + 137.436

T2 =  20 + 137.436

T2 = 157.436 degree Celsius

5 0
3 years ago
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