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BlackZzzverrR [31]
3 years ago
8

The Drop How much time would a 4 kg ball take to fall 1.5 meters?

Physics
1 answer:
zubka84 [21]3 years ago
3 0

Answer:

t = 0.553

Explanation:

The mass has nothing to do with an object falling.

Givens

d = 1.5 m

a = 9.8

vi = 0

t = ?

Formula

d = vi * t + 1/2 a t^2

Solution

1.5 = 0 + 1/2 9.81 * t^2

1.5 = 4.905 t^2

1.5/4.905 = t^2

0.3058 = t^2

sqrt(t^2) = sqrt(0.3058)

t = 0.553

About 1/2 a second which is really surprising wouldn't you think?

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\sf\large \green{\underbrace{\red{Answer⋆}}}:

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\sf R_2   \: and \: R_3 \: are \: in \: parallel \\ \sf so \: let \: the \: total \: of \: R_2 \: and \: R_3 \: be \: R_a

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And there total will be R

\sf R = R_a + R_1 \\  \\  \sf R = 2 + 2 \\  \\  \sf R = 4 \: ohm

(b)

\sf R_1 R_2 \: and \:R_3 \: are \: in \: parallel \: so \: total \: be \: R

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Answer:

\boxed {\boxed {\sf 3.75 \ seconds }}

Explanation:

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\frac{-9 \ m/s }{-2.4 \ m/s^2} =\frac{ -2.4 \ m/s^2*t}{-2.4 \ m/s^2}

\frac{-9 \ m/s }{-2.4 \ m/s^2} =t

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