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3 years ago

14

Earth is slightly closer to the sun in january than in july. How does the area swept out by earth’s orbit around the sun during

the 31 days of january compare to the area swept out during the 31 days of july?

1 answer:

Anna007 [38]3 years ago

8 0

This is because both areas are the same.

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Koala bears can eat only certain kind of Australian eucalyptus leaves.koalas are considered

DaniilM [7]

<em>Hello there, and thank you for asking your question here on brainly.

<u>Answer: Koala bears are considered herbivores, or as in the scientific name, arboreal herbivorous marsupial, marsupial because it also carries it's babies around in a pouch. Koala bears are also native to Australia, which eucalyptus leaves are also native to.
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4 years ago

the word default refers to which of the following a special mode for making changes to a single object the standard layout use f

nirvana33 [79]

Answer:

The standard layout use for new files flat surfaces. etc.

4 0

3 years ago

Volume of a cylinder with a diameter of 1.55 cm and a height of 1.34 cm

Bogdan [553]

Answer:

2.53 cm³

Explanation:

Volume of cylinder = πr²h; where h is the height and r is the radius and

π = 3.14 approx.

Volume = 3.14 * (1.55/2)² * 1.34 = 2.53 cm³

I divided 1.55 by 2 because we were given the diameter and not radius. Diameter = radius / 2

4 0

3 years ago

A slingshot can project a pebble at a speed as high as 38.0 m/s. (a) If air resistance can be ignored, how high (in m) would a p

kipiarov [429]

Answer:

73.67 m

Explanation:

If projected straight up, we can work in 1 dimension, and we can use the following kinematic equations:

$y(t) = y_0 + V_0 * t + \frac{1}{2} a t^2$

$V(t) = V_0 + a * t$ ,

Where $y_0$ its our initial height, $V_0$ our initial speed, a the acceleration and t the time that has passed.

For our problem, the initial height its 0 meters, our initial speed its 38.0 m/s, the acceleration its the gravitational one ( g = 9.8 m/s^2), and the time its uknown.

We can plug this values in our equations, to obtain:

$y(t) = 38 \frac{m}{s} * t - \frac{1}{2} g t^2$

$V(t) = 38 \frac{m}{s} - g * t$

note that the acceleration point downwards, hence the minus sign.

Now, in the highest point, velocity must be zero, so, we can grab our second equation, and write:

$0 m = 38 \frac{m}{s} - g * t$

and obtain:

$t = 38 \frac{m}{s} / g$

$t = 38 \frac{m}{s} / 9.8 \frac{m}{s^2}$

$t = 3.9 s$

Plugin this time on our first equation we find:

$y = 38 \frac{m}{s} * 3.9 s - \frac{1}{2} 9.8 \frac{m}{s^2} (3.9 s)^2$

$y=73.67 m$

6 0

3 years ago

10. Water is a solute in moist air.<br> true or false

Talja [164]

Answer: Yes / true

Explanation: A solute changes the chemical properties of a solvent. Pure water has a higher boiling point than salty water. Ionic compounds dissolve in nonpolar solvents. Water is a solute in moist air.

6 0

3 years ago