1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
yKpoI14uk [10]
2 years ago
9

How many grams of copper (II) hydroxide can be prepared from 2.4 grams of copper (II) nitrate (Cu(NO3)2 ) and excess sodium hydr

oxide?
Chemistry
1 answer:
andreyandreev [35.5K]2 years ago
5 0

Answer:

percentage yield = 67%

Explanation:

Mass of Cu(NO₃)₂  = 15.25 g

Mass of NaOH   = 12.75 g

Percentage yield = ?

Solution:

Cu(NO₃)₂ + 2NaOH   →  Cu(OH)₂ + 2NaNO₃

Moles of Cu(NO₃)₂:

Number of moles = mass/ molar mass

Number of moles = 15.25 g /187.56 g/mol

Number of moles = 0.08 mol

Moles of NaOH :

Number of moles = mass/ molar mass

Number of moles = 12.75 g / 40 g/mol

Number of moles = 0.32 mol

Now we will compare the moles of Cu(OH)₂ with NaOH and Cu(NO₃)₂.      NaOH             :      Cu(OH)₂

                               2                   :          1

                               0.32              :           1/2×0.32 = 0.16 mol

                            Cu(NO₃)₂         :           Cu(OH)₂

                                  1                  :               1

                             0.08                :              0.08

The number of moles produced by  Cu(NO₃)₂  are less so it will limiting reactant.

Mass of Cu(OH)₂:

Mass = number of moles × molar mass

Mass = 0.08 mol × 97.6 g/mol

Mass = 7.808 g

Theoretical yield = 7.808 g

Percent yield:

percentage yield = Actual yield/ theoretical yield ×  100

percentage yield = 5.23 g/  7.808 g ×  100

percentage yield = 0.67 ×  100

percentage yield = 67%

You might be interested in
Calculate the mass of 0.00456 moles of (NH4)2SO4
Anna [14]
To find the mass you need to find the weight of a mol of the molecules by adding up the atomic mass.

N =  14.007 g/mol
H = 1.008 g/mol
S = 32.065 g/mol
O = 16 g/mol

2(14.007) + 8(1.008) + 32.065 + 4(16) = 132.143 g/mol

Now you know how much an entire mol weight you multiply it by how much you actually have 

0.00456 * 132.143 = 0.603 g
7 0
3 years ago
Give an example of each type of intermolecular forces (dispersion,
Andrei [34K]
I’m not too sure I hope someone answers for you
8 0
3 years ago
___CH4 + ___O2 → ___CO2 + ___H2O
DaniilM [7]
CH4 + 2O2 =======> CO2 + 2H2O
5 0
3 years ago
Why are there different theories about the effects of global warming? a. There is no data to support global warming. b. Global c
marin [14]
Option B: 
Global climate is complex, so changes in global climate are hard to predict. 
3 0
2 years ago
what is the density of mercury if 205 mL has a mass of 2790 g; round your answer to the nearest 0.1 g/mL
kherson [118]
D = m / V

D = 2790 g / 205 mL

D = 13.60 g/mL
4 0
3 years ago
Other questions:
  • Two objects are dropped into beaker with layers of oil, rubbing alcohol, water and corn syrup. These objects are made of the sam
    5·1 answer
  • iron-rich minerals in rock pointed in one direction and then switched to the exact opposite direction this supports what idea?
    6·1 answer
  • NaOH is a strong base. What two ions do you expect to find in a solution of NaOH?
    13·1 answer
  • What is the most highly populated rotational level of Cl2 (i) 25deg C and (ii) 100 deg C? Take B=0.244cm-1.This question should
    10·1 answer
  • A student tests two solutions with the same acid-base indicator. If the two solutions have different hydroxide ion concentration
    7·2 answers
  • NEED HELP ASAP!!! I just need to know the order
    9·1 answer
  • Whats the answer giving brainliest have a good day lol help
    15·1 answer
  • SOMEONE HELP ME PLEASE!!! ILL GIVE BRAINLY
    12·1 answer
  • Identify the correct equilibrium constant expression for this equation:
    14·2 answers
  • What kind of waves do light waves travel in and how do they move
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!