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Firdavs [7]
3 years ago
13

A nitrogen gas collected in a tube has a volume of 0.86 mL, a temperature of 316.48 degrees kelvin, and a pressure 1.17 atm. Two

days later, the volume of the nitrogen was 1.06 mL but the pressure did not change. What was the temperature two days later
Chemistry
1 answer:
rewona [7]3 years ago
6 0
Use the formula PV=NRT to find the amount of moles of nitrogen gas. Then use the same formula using the amount of moles found to find the temperature
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Question 5 (5 points)
Dima020 [189]

Answer:

They Are all O's/oberavtions, because inference is using facts and reasoning, which is not the case here.

Explanation:

6 0
3 years ago
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Zinc reacts with excess hydrochloric acid to produce zinc chloride and hydrogen gas. What happens to the reaction rate if you in
agasfer [191]
The correct response I believe is D. The reaction rate increases because the probability of collisions increases as there are more Zn atoms to react.
4 0
4 years ago
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Calculate the mass in micrograms of zinc oxalate the chemist has added to the flask. be sure your answer has the correct number
Vera_Pavlovna [14]
<span>A chemist adds 155.0ml of a 4.10 X 10^-5 mmol/L of a zinc oxalate (ZnC2O4)solution to a reaction flask. Calculate the mass in micrograms of zinc oxalate the chemist has added to the flask. 1mmol = 10^-3 mol Therefore 4.10*10^-5mmol = 4.10*10^-8mol molar mass ZnC2O4 = 65.39+(2*12.011)+(4*15.99) = 153.372g/mol You have 4.10*10^-8 mol/litre =153.372 * 4.10*10^-8 = 6.29*10^-6 grams / litre (* see below) But you have 155ml. Mass of ZnC2O4 = 155/1000*6.29*10^-6 g Mass is = 9.75*10^-7 grams 1µg = 10^-6 g You then have 9.75*10^-7/10^-6 = 0.975µg ZnC2O4 (*see below) at this point you could have said: 1µg = 10^-6 g therefore you have a solution of 6.29µg per litre, 155ml = 6.29*155/1000 = 0.975µg ZnC2O4</span>
3 0
3 years ago
Solution of the Schrödinger wave equation for the hydrogen atom results in a set of functions (orbitals) that describe the behav
kvv77 [185]

Answer :

'n' specifies  → (B) The energy and average distance from the nucleus.

'l' specifies   → (C) The subshell orbital shape.

'ml' specifies → (A) The orbital orientation.

Explanation :

Principle Quantum Numbers : It describes the size of the orbital. It is represented by n. n = 1,2,3,4....

Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

Magnetic Quantum Number : It describes the orientation of the orbitals. It is represented as m_l. The value of this quantum number ranges from (-l\text{ to }+l). When l = 2, the value of

Spin Quantum number : It describes the direction of electron spin. This is represented as m_s. The value of this is +\frac{1}{2} for upward spin and -\frac{1}{2} for downward spin.

As per question we conclude that,

'n' specifies  → The energy and average distance from the nucleus.

'l' specifies   → The subshell orbital shape.

'ml' specifies → The orbital orientation.

5 0
3 years ago
What is the energy transformation in the following:
Tatiana [17]
They all have something to do with electricity
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3 years ago
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