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Aleksandr [31]
3 years ago
5

Which of the following is a potential disadvantage of using wind energy? (2 answers)

Chemistry
1 answer:
Rama09 [41]3 years ago
8 0

Answer:

It's probably b

Explanation:

(I'm wrong aren't I)

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Which of the following pairs of elements is most likely to form an ionic compound?
Scrat [10]

Explanation:

magnesium and sodium because they are minerals and part of iron

5 0
3 years ago
What is the noble-gas configuration for As​
jasenka [17]

Answer:

Noble gas Electronic configuration of arsenic:

As₃₃ = [Ar] 3d¹⁰ 4s² 4p³

Explanation:

Arsenic is metalloid.

Its atomic number is 33.

Its atomic mass is 75 amu.

Its symbol is As.

It is usually present in combine with sulfur and metals.

it is used in bronzing.

It is also used for hardening.

Electronic configuration:

As₃₃ = Is² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p³

Noble gas Electronic configuration:

As₃₃ = [Ar] 3d¹⁰ 4s² 4p³

Noble gas electronic configuration is shortest electronic configuration by using the noble gas elements full octet electronic configuration.

3 0
3 years ago
What is the significance of the Galápagos Islands to the theory of evolution
Aloiza [94]
The importance of the Galapagos to Darwin theory is chances  Darwin discovered several species of finches that varied from island to island .
A big part of reason it is so famous is because of Darwin finches.
which are 12 <span>species ,also the Darwin theory is  only gradually accepted because people don't believe in them today</span>
3 0
3 years ago
Uranium-238 decays to lead-206 with a half-life of 4.5 x 109 yr. Determine how much uranium-238 decays in milligrams (to three s
Mamont248 [21]

Answer:

2.15 mg of uranium-238 decays

Explanation:

For decay of radioactive nuclide-

                        N=N_{0}.(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}

where N is amount of radioactive nuclide after t time, N_{0} is initial amount of radioactive nuclide and t_{\frac{1}{2}} is half life of radioactive nuclide

Here N_{0}=4.60 mg, t=4.1\times 10^{9}yr and t_{\frac{1}{2}}=4.5\times 10^{9}yr

So,N=(4.60mg)\times (\frac{1}{2})^{\frac{4.1\times 10^{9}}{4.5\times 10^{9}}}

so, N = 2.446 mg

mass of uranium-238 decays = (4.60-2.446) mg = 2.15 mg

3 0
3 years ago
wegener used that the same dinosaur fossils have been found in different continents to support his theory of continental drift.
shutvik [7]
The answer to this would be true.
4 0
3 years ago
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