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Aleksandr [31]
3 years ago
5

Which of the following is a potential disadvantage of using wind energy? (2 answers)

Chemistry
1 answer:
Rama09 [41]3 years ago
8 0

Answer:

It's probably b

Explanation:

(I'm wrong aren't I)

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Which of the following is true for balancing equations? A. The number of products should be equal to the number of reactants. B.
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D.) There must be an equal number of atoms of each element on both sides of the equation

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What is the balanced chemical equation for the reaction used to calculate ΔH∘f of SrCO3(s)? If fractional coefficients are requi
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Answer:

Sr(s) + C(s) + 3/2 O₂(g) → SrCO₃(s)

Explanation:

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Sr(s) + C(s) + 3/2 O₂(g) → SrCO₃(s)

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Which statement best explains how the solution should be made? Add 49. 6 mL of 0. 250 M sucrose to 400. 0 mL of water to get 400
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A Biology student wants to conduct a study of how much sunlight affects the length of sleep for mice. She sets up four cages wit
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A solution has [c6h5cooh] = 0.100 m and [ca(c6h5coo)2] = 0.200 m. ka = 6.3 × 10−5 for c6h5cooh. the solution volume is 5.00 l. w
Eddi Din [679]

6.8 is the pH of the solution after 10 ml of 5M NaOH is added.

Explanation:

Data given:

Molarity of C6H5CCOH = 0.100 M

molarity of ca(c6h5coo)2  = 0.2 M

Ka = 6.3 x 10^-5

first pH is calculated of the buffer solution

pH = pKa+ log 10 \frac{[A-]}{[HA]}

pKa = -log10[Ka]

pka = -log[6.3 x10^-5]

pKa = 4.200

putting the values to know pH of the buffer

pH = 4.200 + log 10 \frac{0.2}{0.1}

pH = 4.200 + 0.3

    pH  = 4.5 (when NaOH was not added, this is pH of buffer solution)

now the molarity of the solution is calculated after NaOH i.e Mbuffer is added

MbufferVbuffer = Mbase Vbase

putting the values in above equation:

Mbuffer = \frac{MbaseVbase}{Vbuffer}

             = \frac{5X10}{5000}

             = 0.01 M

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pH = 4.200+ 2.69

pH = 6.8

4 0
3 years ago
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