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Mekhanik [1.2K]
3 years ago
15

HELP PLS HELP i rlly need help omg

Chemistry
1 answer:
sesenic [268]3 years ago
3 0
I think g (sorry if it’s wrong)
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Which type of substance will have the highest boiling point? Select the correct answer below:
nalin [4]

Answer: Option (c) is the correct answer.

Explanation:

Polar molecules are defined as the molecules that chemically combine together and have partial opposite charges.

For example, H_{2}O is a polar molecule as due to the difference in electronegativity of hydrogen and oxygen atom there is partial positive charge on hydrogen atom and partial negative charge on oxygen atom.

On the other hand, molecules which are neutral in nature are known as non-polar molecules. A non-polar molecule is formed by equal sharing of electrons.

For example, CCl_{4} is a non-polar molecule.

As in a large polar molecule, there will be greater force of attraction between the oppositely charged ions due to large surface area. Hence, large amount of heat needs to given in order to break the bonds.

Therefore, we can conclude that a large polar molecule will have the highest boiling point.

5 0
3 years ago
How many mL of 0.013 M potassium hydroxide are required to reach the equivalence point in the titration of 75 mL 0.166 M hydrocy
umka21 [38]

Answer:

957.7mL

Explanation:

Using the formula below;

CaVa = CbVb

Where;

Ca = concentration of acid (M)

Va = volume of acid (mL)

Cb = concentration of base (M)

Vb = volume of base (mL)

According to the information provided in this question:

Ca = 0.166 M

Cb = 0.013 M

Va = 75mL

Vb = ?

Using CaVa = CbVb

0.166 × 75 = 0.013 × Vb

12.45 = 0.013Vb

Vb =12.45/0.013

Vb = 957.7mL

6 0
3 years ago
The equilibrium constant is given for two of the reactions below. Determine the value of the missing equilibrium constant. A(g)
wolverine [178]

Answer:

The correct answer is 8.10

Explanation:

Given:

A(g) + 2B(g) ↔ AB₂(g)   Kc = 59 ---- Eq. 1

A(g) + 3B(g) ↔ AB₃(g)   Kc = 478 ----- Eq. 2

We have to rearrange the chemical equations in order to obtain:

AB₂(g) + B(g) ↔ AB₃(g) Kc = ?

AB₂(g) is a reactant, so we have to use the reverse reaction of Eq. 1, in this case Kc= 1/59. Since AB₃(g) is a product, we use the forward reaction of Eq.2, and the constant is the same: Kc= 478.  The following is the sum of rearranged chemical equations, and the compounds in bold and italic are canceled:

 AB₂(g)       ↔   <em>A(g)</em> + <em>2B(g)</em>          Kc₁= 1/59

<em>A(g)</em> + <em>3B(g)</em> ↔   AB₃(g)                  Kc₂= 478

-----------------------------------------

AB₂(g) + B(g) ↔ AB₃(g)

If we add reactions at equilibrium, the equilibrium constants Kc are mutiplied as follows:

Kc = Kc₁ x Kc₂ = 1/59 x 478 = 478/59 = 8.10

The value of the missing equilibrium constant is 8.10.

6 0
3 years ago
Question 7 of 10
sweet [91]

Answer:

1s2 2s2 2p6 3s2 3p3

Explanation:

8 0
3 years ago
Read 2 more answers
A 50-gram sample has a half-life of 12 days. How much material will remain after 12 days?
Elis [28]
<span>A 50-gram sample with a half-life of 12 days will have a remaining mass of 25 grams after its 12-day half-life. Every cycle of a half-life, the sample will lose half of its mass, so if the half-life, itself, is 12 days and the time period passing is 12 days, one half-life has passed and the material will be halved.</span>
8 0
3 years ago
Read 2 more answers
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