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ivann1987 [24]
3 years ago
10

What are two main types of sedimentary rocks

Chemistry
2 answers:
liubo4ka [24]3 years ago
8 0
I dont really know of this is right but maybe
Clastic Sedimentary Rock and Chemical Sedimentary Rock
Aleks [24]3 years ago
6 0
Granite and pebbles are the answer
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Which radioisotope is used in dating geological formations?i-131u-238ca-37fr-220?
Nostrana [21]
The radioisotope U-238 is primarily used in dating geologic formation. This method is used for dating sediments from either a marine or playa lake environment. Because this method is used for the period between 100,000 years and 1,200,000 years before the present, it aids in bridging the gap between the carbon-14 dating method and the potassium-argon dating method.
6 0
3 years ago
When substances react chemically to create a new substance, will that new substance have the same physical and chemical properti
skad [1K]

Answer:

No it will not have the same chemical properties as the initial substance.

Explanation:

In a chemical change, the atoms in the reactants rearrange themselves and bond together differently to form one or more new products with different characteristics than the reactants

4 0
3 years ago
Water has a density of 0.997 g/cm^3 at 25 degrees C; ice has a density of 0.917 g/cm^3 at -10 degrees C. (question part a) If a
Luden [163]
Mass of water added:
0.997 x 1500
= 1495.5 grams

a) Volume = mass / density
Volume = 1495.5 / 0.917
Volume = 1630 cm³ = 1.63 L

b) The ice cannot be contained in the bottle as its volume exceeds that of the bottle.
4 0
3 years ago
Read 2 more answers
At the normal melting point of NaCl, 801 degrees C, its enthalpy of fusion is 28.8 kJ / mol. The density of the solid is 2.165 g
melisa1 [442]

<u>Answer:</u> The increase in pressure is 0.003 atm

<u>Explanation:</u>

To calculate the final pressure, we use the Clausius-Clayperon equation, which is:

\ln(\frac{P_2}{P_1})=\frac{\Delta H}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

P_1 = initial pressure which is the pressure at normal boiling point = 1 atm

P_2 = final pressure = ?

\Delta H = Enthalpy change of the reaction = 28.8 kJ/mol = 28800 J/mol     (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

T_1 = initial temperature = 801^oC=[801+273]K=1074K

T_2 = final temperature = (801+1.00)^oC=802.00=[802+273]K=1075K

Putting values in above equation, we get:

\ln(\frac{P_2}{1})=\frac{28800J/mol}{8.314J/mol.K}[\frac{1}{1074}-\frac{1}{1075}]\\\\\ln P_2=3\times 10^{-3}atm\\\\P_2=e^{3\times 10^{-3}}=1.003atm

Change in pressure = P_2-P_1=1.003-1.00=0.003atm

Hence, the increase in pressure is 0.003 atm

6 0
3 years ago
How must atoms change so that they can join to form an ionic compound
Zina [86]
Atoms must gain or lose electrons in order to become ions if they are to form ionic bonds.
7 0
2 years ago
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