If the mass of the original sample of Galium-68 is 10 mg, then . . .
== After one half-life, (1/2)(10 mg) = 5 mg remain
== After the second half-life, (1/2)(5 mg) = 2.5 mg remain
== After the third half-life, (1/2)(2.5 mg) = 1.25 mg remain
It doesn't matter how long the half-life is.
Answer:
The resulting velocity of marble B after the collision is 0.96 m/s.
Explanation:
Mass of marble A ,
Initial velocity of the marble A,
Mass of marble B,
Initial velocity of the marble B,
final velocity of the marble A,
final velocity of the marble B,
Applying law of conservation of mass:
The resulting velocity of marble B after the collision is 0.96 m/s.
Answer:
0.546
Explanation:
From the given information:
The force on a given current-carrying conductor is:
where the length usually in negative (x) direction can be computed as
Now, taking the integral of the force between x = 1.0 m and x = 3.0 m to get the value of the force, we have:
where;
current I = 7.0 A
F = 546 × 10⁻³ T/mT
F = 0.546