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2 years ago

Find the magnitude of the electric force on a 2.0 uC charge in a 100n/C electric field.

Physics

1 answer:

Eva8 [605]2 years ago

4 0

Answer:

Electric force will be equal to $2\times 10^{-4}N$

Explanation:

We have given charge $q=2\mu C=2\times 10^{-6}C$

Electric field will be $E=100N/C$

We have to find the magnitude of force

Electric force is the multiplication of electric field and charge

So electric force $F=qE=2\times 10^{-6}\times 100=2\times 10^{-4}N$

Electric force will be equal to $2\times 10^{-4}N$

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3 years ago

A projectile is fired from the ground at a velocity of 30.0 m/s, 35.0 º from the horizontal. What is the maximum height the proj

Norma-Jean [14]

Answer:

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2 years ago

Answer True or Flase1-Electric potential due to a uniform E field doesn’t change with location.2-The equipotential surfaces asso

TEA [102]

Answer:

1. False

2. True

3. True

Explanation:

1- False —> The relation between electric potential and electric field is given such that

$-\int\limits^a_b \vec{E}d\vec{l} = V_{ab}$

Therefore, for a uniform E field, electric potential is linearly proportional to the distance.

2- True —> The electric field lines always cross the equipotential lines perpendicularly.

3- True —> In order to be a potential difference, one source of electric field is enough. The electric potential will decrease radially according to the following formula:

$V = \frac{1}{4\pi\epsilon_0}\frac{q}{r^2}$

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3 years ago

A 57.0 kg cheerleader uses an oil-filled hydraulic lift to hold four 120 kg football players at a height of 1.10 m. If her pisto

lapo4ka [179]

Answer:

The diameter of the piston of the players equals 55.136 cm.

Explanation:

from the principle of transmission of pressure in a hydraulic lift we have

$\frac{F_{1}}{A_{1}}=\frac{F_{2}}{A_{1}}$