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2 years ago

Find the magnitude of the electric force on a 2.0 uC charge in a 100n/C electric field.

Physics

1 answer:

Eva8 [605]2 years ago

4 0

Answer:

Electric force will be equal to $2\times 10^{-4}N$

Explanation:

We have given charge $q=2\mu C=2\times 10^{-6}C$

Electric field will be $E=100N/C$

We have to find the magnitude of force

Electric force is the multiplication of electric field and charge

So electric force $F=qE=2\times 10^{-6}\times 100=2\times 10^{-4}N$

Electric force will be equal to $2\times 10^{-4}N$

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A makeshift swing is constructed by making a loop in one end of a rope and tying the other end to a tree limb. A child is sittin

sveticcg [70]

Answer:

a) 264.74 N

b) 91.15 N

c) 20.12°

Explanation:

Given:

Angle between the rope and the vertical, θ = 19°

Tension in the rope, T = 280 N

For the system to be in equilibrium,

The net force in vertical as well as in horizontal direction, should be zero

Therefore,

a) For Vertical direction

Weight of the child = vertical component of the tension

W = T cosθ ..............(1)

W = 280 cos19° = 264.74 N ............(a)

b) For horizontal

force on the child, F = T sinθ .............(2)

F = 280 sin19° = 91.15 N

c) Now, on dividing (1) and (2), we have

W/F = Tcosθ/Tsinθ

tanθ = F/W

now, for F = 97 N

tanθ = 97/264.74 = 0.3663 (W from (a))

θ = tan⁻¹(0.3663)

θ = 20.12°

3 0

2 years ago

Air is being pumped into a spherical balloon so that its volume increases at a rate of 150 cm3/s. How fast is the radius of the

Slav-nsk [51]

0.119cm/s is the radius of the balloon increasing when the diameter is 20 cm.

<h3>How big is a circle's radius?</h3>

The radius of a circle is the distance a circle's center from any point along its circumference. Usually, "R" or "r" is used to indicate it.

A circle's diameter cuts through the center and extends from edge to edge, in contrast to a circle's radius, which extends from center to edge. Essentially, a circle is divided in half by its diameter.

dv/dt = 150cm³/s

d = 2r = 20cm

r = 10cm

find dr/dt

Given that the volume of a sphere is calculated using

v = 4/3πr³

Consider both sides of a derivative

d/dt(v) = d/dt( 4/3πr³)

dv/dt = 4/3π(3r²)dr/dt = 4πr²dr/dt

Hence,

dr/dt = 1/4πr².dv/dt

dr/dt = 1/4π×(10)²×150

dr/dt = 1/4π×100×150

dr/dt = 0.119cm/s.

To know more about radius visit:

brainly.com/question/15053236

#SPJ4

3 0

5 months ago

A 0.0502-kg pair of fuzzy dice is attached to the rearview mirror of a car by a short string. The car accelerates at constant ra

Sauron [17]

Answer:

a = 0.55 m/s/s

Explanation:

As the car accelerates in forward direction the string will make some angle with the vertical direction

So here horizontal component of the tension force will accelerates the dice in forward direction along with the car

Vertical component of the tension force will balance the weight of the dice

so we will have

$Tcos\theta = mg$

$Tsin\theta = ma$

here we know that

$\theta$ = angle made with the vertical by string

now divide the two equations

$\frac{sin\theta}{cos\theta} = \frac{ma}{mg}$

so we have

$a = g tan\theta$

$a = 9.81 tan3.20$

$a = 0.55 m/s^2$

7 0

2 years ago

A particle moving along the x-axis has a position given by x = (24t – 2.0t 3 ) m, where t is measured in s. What is the magnitud

Vitek1552 [10]

<h2>The magnitude 24 ( $\dfrac{m}{s^2}$ ) of the acceleration of the particle when the particle is not moving.</h2>

Explanation:

Given,

A particle moving along the x-axis has a position given by

$x=(24t-2.0t^3)$ m ........ (1)

To find, the magnitude ( $\dfrac{m}{s^2}$ ) of the acceleration of the particle when the particle is not moving = ?

Differentiating equation (1) w.r.t, 't', we get

$\dfrac{dx}{dt} =\dfrac{d((24t-2.0t^3))}{dt}$

⇒ $\dfrac{dx}{dt} =24(1)-3(2.0)t^{2} =24-6t^{2}$ ....... (2)

⇒ $24-6t^{2} = 0$

⇒ $t^{2}=2^{2}$

⇒ t = 2 s

Again, differentiating equation (2) w.r.t, 't', we get

$\dfrac{d^2x}{dt^2} =-12t$

Put t = 2, we get

$\dfrac{d^2x}{dt^2} =-12(2)=24$

Thus, the magnitude 24 ( $\dfrac{m}{s^2}$ ) of the acceleration of the particle when the particle is not moving.

3 0

2 years ago

Where does the shadow of the shuttle in space form?

vekshin1

The shadow forms on the first surface away from the shuttle in the direction opposite the sun.

8 0

2 years ago