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2 years ago

Find the magnitude of the electric force on a 2.0 uC charge in a 100n/C electric field.

Physics

1 answer:

Eva8 [605]2 years ago

4 0

Answer:

Electric force will be equal to $2\times 10^{-4}N$

Explanation:

We have given charge $q=2\mu C=2\times 10^{-6}C$

Electric field will be $E=100N/C$

We have to find the magnitude of force

Electric force is the multiplication of electric field and charge

So electric force $F=qE=2\times 10^{-6}\times 100=2\times 10^{-4}N$

Electric force will be equal to $2\times 10^{-4}N$

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Consult Interactive Solution 10.37 to explore a model for solving this problem. A spring is compressed by 0.0647 m and is used t

padilas [110]

Answer:

$\omega=32.14\ rad/s$

Explanation:

Given that,

The compression in the spring, x = 0.0647 m

Speed of the object, v = 2.08 m/s

To find,

Angular frequency of the object.

Solution,

We know that the elation between the amplitude and the angular frequency in SHM is given by :

$v=\omega\times A$

A is the amplitude

In case of spring the compression in the spring is equal to its amplitude

$\omega=\dfrac{v}{A}$

$\omega=\dfrac{2.08\ m/s}{0.0647\ m}$

$\omega=32.14\ rad/s$

So, the angular frequency of the spring is 32.14 rad/s.

4 0

3 years ago

Find the force required to do 25 joule work when the force causes a displacement of 0.5 m

Eduardwww [97]

Answer:

Explanation:

The force required can be found by using the formula

$f = \frac{w}{d} \\$

w is the workdone

d is the distance

From the question we have

$f = \frac{25}{0.5} \\$

We have the final answer as

Hope this helps you

6 0

2 years ago

Body 1 has a mass m, and its moving in a circle with a radius r at a speed v. It has a centripetal force. F acting on it. If bod

cluponka [151]

Answer:

The centripetal force on body 2 is 8 times of the centripetal force in body 1.

Explanation:

Body 1 has a mass m, and its moving in a circle with a radius r at a speed v. The centripetal force acting on it is given by :

$F=\dfrac{mv^2}{r}$

Body 2 has a mass 2m and its moving in a circle of radius 4r at a speed 4v. The centripetal force on body 2 is :

$F'=\dfrac{2m\times (4v)^2}{4r}\\\\F'=\dfrac{2m\times 16v^2}{4r}\\\\F'=8\dfrac{mv^2}{r}\\\\F'=8F$

So, the centripetal force on body 2 is 8 times of the centripetal force in body 1.

8 0

2 years ago

A spaceprobe has an 29.0 m length when measured at rest. What length

elixir [45]

Answer:

The observer sees the space-probe 9.055m long.

Explanation:

Let $L_0$ be the length of the space-probe when measured at rest, and $L$ be its length as observed by an observer moving at velocity $v$ , then

$(1).\: \: L = L_0\sqrt{1-\dfrac{v^2}{c^2} }$

Now, we know that $L_0 = 29.0m$ and $v = 0.95c$ , and putting these into $(1)$ we get:

$L = 29\sqrt{1-\dfrac{(0.95c)^2}{c^2} }$

$L = 29\sqrt{1-0.95^2 }$

$\boxed{L = 9.055m}$

Thus, an observer moving at 0.95c observes the space-probe to be 9.055m long.

3 0

3 years ago

How does the motion of atoms relate to hot air balloons?

Neporo4naja [7]

Magic magic and more magic

6 0

3 years ago