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lord [1]
3 years ago
7

What is photosynthesis​

Physics
2 answers:
Viktor [21]3 years ago
8 0

Answer:

photosynthesis is the process by which plant prepares food using carbondioxide and water in the presence of sunlight

Vinil7 [7]3 years ago
8 0

Explanation:

the process by which green plant turn carbon dioxide and water into food using energy from sunlight

You might be interested in
Compute the specific heat capacity at constant volume of nitrogen (N2) gas. The molar mass of N2 is 28.0 g/mol.
jekas [21]

Answer:

724.3J/Kg.K

Explanation:

CHECK THE COMPLETE QUESTION BELOW

Compute the specific heat capacity at constant volume of nitrogen (N2) gas.and compare with specific heat of liquid water. The molar mass of N2 is 28.0 g/mol.

The specific heat capacity can be computed by using expression below

c= CV/M

Where c= specific heat capacity

M= molar mass

CV= molar hear capacity

Nitrogen is a diatomic element, the Cv can be related to gas constant with 5/2R

Where R= 8.314J/mol.k

Molar mass= 28 ×10^-3Kg/mol

If we substitute to the expression, we have

c= (5R/2)/(M)

=5R/2 × 1/M

=(5×8.314) /(2×28 ×10^-3)

=724.3J/Kg.K

Hence, the specific heat capacity at constant volume of nitrogen (N2) gas is

724.3J/Kg.K

The specific heat of liquid water is about 4182 J/(K kg) which is among substance with high specific heat, therefore specific heat of Nitrogen gas is 724.3J/Kg.K which is low compare to that of liquid water.

4 0
3 years ago
A solution of phosphoric acid was made by dissolving 10.0 g H3PO4 in 100.0 mL water. The resulting volume was 104 mL. Calculate
OLEGan [10]

Answer:

density is 1.057 g/mL

mole fraction is 0.0180

molarity is 0.98 mol/L

mole fraction is 0.0180

Explanation:

Given data

acid mass = 10 g

water volume = 100 mL

total volume = 104 mL

density = 1 g/cm³

to find out

the density, mole fraction, molarity, and molality

solution

first we calculate the density that is = total mass g / volume of solution mL

total mass = mass of H3PO4 + water  mass

so water mass = density x volume

water mass = 100 ml x 1.0  g/cm3

water mass = 100 g  

so total mass  = 110.00 g

so that

density = total mass g / volume of solution mL

density = 110 / 104 = 1.057 g/mL

now we calculate no of moles in solvent i.e = mass  H2O / mlar mass H2O

no of moles in solvent = 100/18.015 = 5.55 moles

and no of moles in solute i.e = mass of H3PO4 / mlar mass in H3PO4

moles in solute i.e = 10/ 97.994 = 0.102 moles

so total moles is  5.55  + 0.102 = 5.652 moes

so now mole fraction = no of moles in solute / total moes

mole fraction = 5.55 / 5.65

mole fraction is 0.0180

now we calculate first

mole fraction in solute and solvent that is

mole fraction in solute = no of moles in solute/ total moles

mole fraction in solute = 0.102 /5.65

mole fraction in solute is 0.0180

and mole fraction in solvent that = no of moles in solvent/ total moles

mole fraction in solvent that = 5.55/ 5.65

mole fraction in solvent that is 0.982

so molarity = no of moles of solute / volume

molarity = 0.102/0.104

molarity is 0.98 mol/L

and molality  is = no of moles of solute / mass

molality = 0.102 / 100

molality  is  1.02 mol/kg

6 0
3 years ago
This question is typical on some driver’s license exams: A car moving at 45 km/h skids 15 m with locked brakes. How far will the
sergiy2304 [10]

from kinematics equation if we know that final speed is ZERO and initial speed is given that due to constant deceleration the object will stop in some distance "d" and this distance can be calculated by kinematics

v_f^2 - v_i^2 = 2 a d

0 - v^2 = 2(a)d

here acceleration due to friction will be same at all different speed

so for 45 km/h speed the distance of stop is 15 m

while at other speed 112.5 km/h the distance will be unknown

now we will have

0 - 45^2 = 2(a)15

0 - 112.5^2 = 2(a)d

now divide above two equations

\frac{45^2}{112.5^2} = \frac{15}{d}

d = 93.75 m

So it will stop in distance 93.75 m

8 0
3 years ago
A uniform stick has a mass of 4.42 kg and a length of 1.23 m. It is initially lying flat at rest on a frictionless horizontal su
nataly862011 [7]

10.7 rad/s is the final angular velocity of the stick.

Given:

Mass of the stick = 4.42 kg

Length of the stick = 1.23m

Force of impulse (I) = 12.8 N s

The linear velocity of the stick, v=\frac{I}{m}

                                                  v=\frac{12.8 N.s (\frac{1 kg m/s^2}{1 N}) }{4.42 kg}

                                                  v  = 2.89 m/s

Therefore, the final linear velocity of the stick is 2.89 m/s

∴w=\frac{12 Ir}{ml^{2} }

w=\frac{12 ( 12.8 N.s ) ( 46.4 cm)}{(4.42 kg) (1.23 m)^2}

w= \frac{12 (12.8 N.s) (46.4 cm) (\frac{10^-^2 m}{1 cm} )}{(4.42 kg) (1.23m)2}

w=10.7   rad/s

Therefore, 10.7 rad/s is the final angular velocity of the stick.

Learn more about linear velocity here:

brainly.com/question/15154527

#SPJ4

                                                 

5 0
2 years ago
Very small particles moving in viscous fluids experience a drag force proportional to
Likurg_2 [28]

Answer:

t = 3w/gk

y = w²/gk²(2+e^-gkt/t)

Explanation:

The detailed step by step solution can be found in the attachment below.

Vt = W/k. It is the velocity of the body when the drag force = the weight of the particle.

I steps have been explaine6in the attachments below.

3 0
3 years ago
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