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Mnenie [13.5K]
3 years ago
6

Please help asap!!!!!!!!!!!!!!!!!!! will give brainliest

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
4 0

Answer:

no lo se

Step-by-step explanation:

44

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H(1) = -26<br>h(n) = h(n − 1).(-9)<br>Find an explicit formula for h(n).​
a_sh-v [17]

Answer:

H(n) = 234⁽ⁿ⁻¹⁾

Step-by-step explanation:

Hello,

The first thing to do when finding an explicit equation is to determine if the sequence is arithmetic or geometric.

In this question, the sequence is a geometric progression.

h(n) = h⁽ⁿ⁻¹⁾.(-9)

a = -26

r = common difference

a(n) =ar⁽ⁿ⁻¹⁾

h(n) = -26 × (-9)hⁿ⁻¹⁾

h(n) = 234⁽ⁿ⁻¹⁾

8 0
3 years ago
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The figure is made up of a rectangle and 2 right triangles.
sladkih [1.3K]
<span>1259 units2 i hope this helps you</span>
7 0
3 years ago
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This Histogram shows the average speed in miles per hour of cars traveling along a state highway one afternoon. Which informatio
kari74 [83]

Answer:The alternative hypothesis is that the mean speed of drivers on this highway is less than 65 mph.

Step-by-step explanation:

i hope this helps and I'm sorry if this is wrong.

6 0
2 years ago
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The equivalent ratios show how many teaspoons there are in 5 cups. What method can be used to convert 1 cup to teaspoons?
yarga [219]

A. multiply 1,200 by 5

Step-by-step explanation:

Because to convert it to you would have to convert it you'd have to multiply the number above to receive your sum.

6 0
4 years ago
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I need help with this problem
alexandr402 [8]

Answer:

4*x^4*y^22

Step-by-step explanation:

Your goal here is to REDUCE the given expression to simplest terms.

One way in which to approach this problem would be to rewrite (2x^2y^10)^3 as:  (2x^2*y^8)*y^2*(2x^2*y^10)^2.

Dividing this rewritten expression by 2x^2*y^8 results in:

y^2(2x^2*y^10)^2.

We now need to raise (2x^2*y^10) to the power 2.  Doing this, we get:

4x^4*y^20.

Multiply this by y^2 (see above):

y^2*4x^4*y^20

The first factor is 4:  4y^2*x^4*y^20.  This is followed by the product of y^2 and y^20:                   4*y^22*x^4

Finally, this should be re-written as

                                    4*x^4*y^22

Another way of doing this problem would involve expanding the numerator fully and then cancelling out like factors:

8*x^6*y^30      4*x^4*y^22

----------------- = ------------------ = 4*x^4*y^22

  2x^2y^8                  1

7 0
3 years ago
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