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EleoNora [17]
3 years ago
5

In the United States, barometric pressures a re generally reported in inches of mercury (in. Hg). On a beautiful summer day in C

hicago, the barometric pressure is 30.45 in. Hg. Convert this pressure to torr.
Chemistry
1 answer:
Svetllana [295]3 years ago
7 0

Answer:

773.43 torr

Explanation:

From the question given above, the following data were obtained:

Pressure (in inHg) = 30.45 inHg

Pressure (in torr) =?

We can convert 30.45 inHg to torr by doing the following:

1 inHg = 25.4 torr

Therefore,

30.45 inHg = 30.45 inHg × 25.4 torr / 1 inHg

30.45 inhg = 773.43 torr

Thus, 30.45 inhg is equivalent to 773.43 torr

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Answer:

For evaporation you need a warm, preferably humid temperature. The rate of evaporation increases with an increase in temperature. A windy climate is best, as wind helps to remove the evaporated water vapour, and therefore creating a better scope for evaporation to continue. The speed of wind is important for evaporation because the wind pulls in dry air, increasing the rate of evaporation.

Short Answer- Hot and humid temperature, lots of wind speed.

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3 years ago
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Why is a changing ocean temperature of only one or 2 degrees so concerning? Please help!!!!
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For each of the bonds listed, tell which atom is more negatively charged a. C--H b. C--N c. C--S d. C--O
blondinia [14]

Explanation:

The atom is considered to be more electronegative , when it has the tendency to get a slight negative i.e. , delta negative charge on it , and the other atom gets a delta positive charge .

In the periodic table ,

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and

As we go top to bottom , the electronegativity decreases .

Hence , from the option given in the question ,

a. C--H , the electronegativity of both the atom is almost the same , but looking at the treads of the periodic table , Carbon is more electronegative than hydrogen .

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c. C--S , the electronegativity of both the atom is almost the same , but looking at the treads of the periodic table , sulfur is more electronegative than Carbon .

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5 0
3 years ago
What is the change in boiling point for a 0.615m solution of Mgl2 in water?
ivanzaharov [21]

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Explanation :

Formula used :

\Delta T_b=i\times K_f\times m

where,

\Delta T_b = change in boiling point = ?

i = Van't Hoff factor = 3 (for MgI₂ electrolyte)

K_f = boiling point constant for water = 0.51^oC/m

m = molality  = 0.615 m

Now put all the given values in this formula, we get

\Delta T_b=3\times (0.51^oC/m)\times 0.615m

\Delta T_b=0.94^oC

Therefore, the change in boiling point is, 0.94^oC

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PEER COUNSELING 2 HELP! 13 POINTS
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D. or C. I think it is more D. than anything else

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