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EleoNora [17]
3 years ago
5

In the United States, barometric pressures a re generally reported in inches of mercury (in. Hg). On a beautiful summer day in C

hicago, the barometric pressure is 30.45 in. Hg. Convert this pressure to torr.
Chemistry
1 answer:
Svetllana [295]3 years ago
7 0

Answer:

773.43 torr

Explanation:

From the question given above, the following data were obtained:

Pressure (in inHg) = 30.45 inHg

Pressure (in torr) =?

We can convert 30.45 inHg to torr by doing the following:

1 inHg = 25.4 torr

Therefore,

30.45 inHg = 30.45 inHg × 25.4 torr / 1 inHg

30.45 inhg = 773.43 torr

Thus, 30.45 inhg is equivalent to 773.43 torr

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timurjin [86]

the answer is The average kinetic energy of the surrounding air particles increases.


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7 0
3 years ago
A vapor is which state of matter?<br><br> a. solid<br> b. liquid <br> c. gas<br> d. all of the above
Yanka [14]
A vapor is which state of matter?

C. Gas.
8 0
3 years ago
Matching
kotegsom [21]

Answer:

a mixture of molecules - Box f

atoms of a pure elementa metal - Box D

a solid compound - Box C

a mixture of elements - Box A

Explanation:

Box a has mixture of elements which forms a solid like shape but there are different elements present in the box. The box f has mixture of molecules in which many atoms are combined together. Box c has solid compound with single element.

5 0
3 years ago
Match the boxes helppppppp
lesantik [10]

Answer:

?

Explanation:

3 0
3 years ago
Cu(s) + 4 HNO3 (aq) --&gt; Cu(NO3)2 (aq) + 2NO2 (g) + 2H2O(l)
GREYUIT [131]

Answer:

The percent by mass of copper in the mixture was 32%

Explanation:

The ammount of HNO₃ used is:

mol HNO₃ = volume * concentration

mol HNO₃ = 0.015 l * 15.8 mol/l

mol HNO₃ = 0.237 mol

According to the reaction, 4 mol HNO₃ will react with 1 mol Cu and produce 1 mol Cu²⁺. Since we have 0.237 mol HNO₃, the amount of Cu that could react would be (0.237 mol HNO₃ * 1 mol Cu / 4 mol HNO₃) 0.06 mol. This reaction would produce 0.060 mol Cu²⁺, however, only 0.010 mol Cu²⁺ were obtained, indicating that only 0.010 mol Cu were present in the mixture. This means that the acid was in excess, so we can assume that all copper present in the mixture has reacted.

Since 0.010 mol of Cu²⁺ were produced, the amount of Cu was 0.01 mol.

1 mol of Cu has a mass of 63.5 g, then 0.01 mol has a mass of:

0.01 mol Cu * 63.5 g / 1 mol = 0.635 g.

Since this amount was present in 2.00 g mixture, the amount of copper in 100 g of the mixture will be:

100 g(mixture) * 0.635 g Cu / 2 g(mixture) = 32 g

Then, the percent by mass of Cu (which is the mass of Cu in 100 g mixture) is 32%

6 0
3 years ago
Read 2 more answers
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