hard because it has calcium and magnesium
Balanced equation
Mg₃(PO₄)₂ + 2Al(NO₃)₃ → 3Mg(NO₃)₂ + 2AlPO₄
<h3>Further explanation</h3>
Given
Reaction
Mg3(PO4)2 + Al(NO3)3 → Mg(NO3)2 + AlPO4
Required
Balanced equation
Solution
Give a coefficient :
Mg₃(PO₄)₂ + aAl(NO₃)₃ → bMg(NO₃)₂ + cAlPO₄
Make an equation :
Mg, left = 3, right=b⇒b=3
P, left=2, right=c⇒c=2
Al, left=a, right=c⇒a=c⇒a=2
The reaction becomes :
Mg₃(PO₄)₂ + 2Al(NO₃)₃ → 3Mg(NO₃)₂ + 2AlPO₄
It is both a and b
nuclear rxns will ALWAYS have changes in both mass and some of that mass will be converted into energy.
Answer:
the molar mass for fluorine is 37.99681 g/mol
Using the ideal gas law PV =nRTPV=nRT , we find that the pressure will be P =\frac{nRT}{V}P=
V
nRT
. Then, we'll substitute and find the pressure, using T = -25 °C = 248.15 K and R = 0.0821 \frac{atm\cdot L}{mol \cdot K}
mol⋅K
atm⋅L
:
P =\frac{nRT}{V} = \frac{(0.33\,\cancel{mol})(0.0821\frac{atm\cdot \cancel{L}}{\cancel{mol \cdot K}})(248.15\,\cancel{K})}{15.0\,\cancel{L}} = 0.4482\,atmP=
V
nRT
=
15.0
L
(0.33
mol
)(0.0821
mol⋅K
atm⋅
L
)(248.15
K
)
=0.4482atm
In conclusion, the pressure of this gas is P=0.4482 atm.
Reference:
Chang, R. (2010). Chemistry. McGraw-Hill, New York.
