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MissTica
3 years ago
6

Calculate the density of gold (in units of g/mL) if a 5.00 cm cube has a mass of 2.41kg

Chemistry
2 answers:
ikadub [295]3 years ago
6 0
Turn 2.41 kg into grams :

2.41 * 1000 => 2,410 g

1 cm³ = 1 mL , so:

5.00 cm³ = 5.00 mL

Therefore:

D = mass / volume

D = 2,410 / 5.00

D = 482 g/mL



levacccp [35]3 years ago
5 0
The volume of a 5cm cube is 0.5dm*0.5dm*0.5dm = 0.125dm^3
1dm^3 = 1l
So 0.125dm^3 = 125mL
This gives us 2410/125 = 19.28
So the density of gold is 19.28g/mL
Final check: Gold is indeed 19.3g/mL
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Draw the diazonium cation formed when cytosine reacts with nano2 in the presence of hcl.
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Answer in the Word document below.
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7 0
3 years ago
Which of the following would NOT diffuse through the plasma membrane by means of simple diffusion?1 oxygen2 glucose3 a steroid h
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Answer:

Option 2= Glucose

Explanation:

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Facilitated diffusion:

it is a type of diffusion in which caries protein without using the cellular energy shuttle the molecules to the cell membrane. Glucose is bind on the carrier protein ,change the shape and transport it from one to another side of membrane. In order to absorb the glucose red blood cells use this kind of diffusion.

Primary active transport:

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Secondary active transport:

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5 0
3 years ago
At 0 degrees Celsius, a gas occupies 22.4L. How hot must the gas be in celcius to reach a volume of 25.0L
NikAS [45]

Answer:

31.7 °C

Explanation:

Charles law states that for volume of a gas is directly proportional to the absolute temperature for a fixed amount of gas at constant pressure

we can use the following equation

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where V1 is volume and T1 is temperature at first instance

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substituting the values in the equation

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T2 = 304.7 K

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3 years ago
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