Question

Find the polar angle (in radians with respect to +x-axis) of −3i + j.

Answer 1

Answer:

$-18.43^{\circ}$

Explanation:

Let $\theta$ be the polar angle of −3i + j. We can find it using the formula as follows :

$\tan\theta=\dfrac{y}{x}\\\\\tan\theta=\dfrac{1}{-3}\\\\\theta=\tan^{-1}(\dfrac{1}{-3})\\\\\theta=-18.43^{\circ}$

So, the required polar angle is $-18.43^{\circ}$.