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viktelen [127]
2 years ago
6

A woman pulls a 7.87 kg suitcase,

Physics
1 answer:
Lelechka [254]2 years ago
6 0

Answer:

Effective Pulling Force = 29.2(cos 62.7°) = 13.393 N

Resistance to Pulling Force = 11.7 N

Net Force acting on suitcase = 13.393 - 11.7 = 1.693 N

Distance moved = 8.44 m

Net Work = 1.693(8.44) = 14.289 ≈ 14.3 J  ANS

Explanation:

hope that makes sense homie

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2 years ago
Hello!
Montano1993 [528]

It is true that the  light is 15.000 more dangerous than the radiation of a microwave.

<h3>What is the wavelength?</h3>

The wavelength shows the extent or how far the wave travels. Now we know that the energy of the wave can be use to find out how much dangerous the wave is.

Now;

1.6 * 10^-19 J = 1eV

x J = 1.8 eV

x = 1.8 eV * 1.6 * 10^-19 J /1eV

x = 2.88 * 10^-19 J

Now if the energy of the microwaves is 1.2 x 10^-4 J, then it follows that;

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Hence, it is true that the  light is 15.000 more dangerous than the radiation of a microwave.

Learn more about microwave:brainly.com/question/15708046

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5 0
2 years ago
Which observation would be evidence that heat was transferred by radiation?
oksian1 [2.3K]
I think the answer is D
8 0
2 years ago
An electron is accelerated from rest through a potential difference. After acceleration the electron has a de Broglie wavelength
Vladimir [108]

Answer:

3x10⁴v

Explanation:

Using

Wavelength= h/ √(2m.Ke)

880nm = 6.6E-34/√ 2.9.1E-31 x me

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4 0
3 years ago
If the electron has half the speed needed to reach the negative plate, it will turn around and go towards the positive plate. Wh
In-s [12.5K]

Answer:

 v = -v₀ / 2

Explanation:

For this exercise let's use kinematics relations.

Let's use the initial conditions to find the acceleration of the electron

            v² = v₀² - 2a y

when the initial velocity is vo it reaches just the negative plate so v = 0

           a = v₀² / 2y

now they tell us that the initial velocity is half

          v’² = v₀’² - 2 a y’

          v₀ ’= v₀ / 2

at the point where turn v = 0              

          0 = v₀² /4  - 2 a y '

          v₀² /4 = 2 (v₀² / 2y)  y’

          y = 4 y'

          y ’= y / 4

We can see that when the velocity is half, advance only ¼ of the distance between the plates, now let's calculate the velocity if it leaves this position with zero velocity.

         v² = v₀² -2a y’

         v² = 0 - 2 (v₀² / 2y) y / 4

         v² = -v₀² / 4

         v = -v₀ / 2

We can see that as the system has no friction, the arrival speed is the same as the exit speed, but with the opposite direction.

7 0
3 years ago
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