Answer:
Distance, S = 13m
Explanation:
Given the following data;
Initial velocity, u = 4m/s
Final velocity, v = 9m/s
Time, t = 2 seconds
To find the distance, S;
First of all, we would determine the acceleration of the shark.
Acceleration = (v - u)/t
Acceleration = (9 - 4)/2
Acceleration = 5/2
Acceleration = 2.5m/s²
Now, to find the distance we would use the second equation of motion
S = ut + ½at²
Substituting into the equation, we have
S = 4(2) + ½*2.5*2²
S = 8 + 1.25*4
S = 8 + 5
Distance, S = 13m
Explanation:
According to the fundamental law of electrostatics, like charges which are ( only positive or only negative charges) repel while unlike charges which are ( positive and negative charges ) attract each other.
that is: ( +++++ ++++++) they repel
while ( +++++++ ———) they attract
Answer: the pitch would be higher than it was at a lower speed because the air in front of the jet is compressed
<span>Mass of the electron = 9.1 x 10 ^ -28g = 9.1 x 10 ^ -31kg
Velocity of the electron = 1.7 x 10 ^ 4
We have Planck Constant h = 6.626 x 10 ^ -34
Wavelength of the electron w = h/mv
w = 6.626 x 10 ^ -34 / ((9.1 x 10 ^ -31)(1.7 x 10 ^ 4))
= 6.626 x 10 ^ -34 / 15.47 x 10 ^ -27
= 0.428312 x 10 ^ -7
= 4.28 x 10 ^ -8 m</span>
