First, we determine the mass of each element from the data collected. We can get the mass of molybdenum Mo from the difference between the mass of crucible and molybdenum and the mass of crucible:
Mass of molybdenum = 39.52 – 38.26 = 1.26 g Mo
We can calculate for the mass of molybdenum oxide from the difference between the mass of crucible and molybdenum oxide and the mass of crucible:
Mass of molybdenum oxide = 39.84 – 38.26 = 1.58g
We can now compute for the mass of oxygen O by subtracting the mass of molybdenum from the mass of molybdenum oxide:
Mass of oxygen in molybdenum oxide = 1.58 – 1.26 = 0.32g O
To convert mass to moles, we use the molar mass of each element.
1.26 g Mo * 1 mol Mo / 95.94 g Mo = 0.0131 mol Mo
0.32 g O * 1 mol O / 15.999 g O = 0.0200 mol O
0.0131 mol is the smallest number of moles. We divide each mole value by this number:
0.0131 mol Mo / 0.0131 = 1
0.0200 mol O / 0.0131 = 1.53
Multiplying these results by 2 to get the lowest whole number ratio,
0.0131 mol Mo / 0.0131 = 1 * 2 = 2
0.0200 mol O / 0.0131 = 1.5 * 2 = 3
Thus, we can write the empirical formula as Mo2O3.
Answer:
B
Explanation:
Balanced equations have the same number of elements on both sides. If the number of elements are equal to each other for every element in the equation on both sides, then the equation is balanced.
Important concept : The big number before an element or compound represents how many molecules of that compound or element there are in a reaction. To find the number of atoms of each element you multiply the coefficient by the subscript ( small number ) which represents the number of atoms of that element in each molecule. Ex. 3H2O. There is a coefficient of 3 meaning that there are 3 molecules of H2O. There is a subscript after H meaning there are 2 atoms of hydrogen in each molecule. To find the total number of atoms we multiply the subscript of hydrogen by the coefficient of the whole molecule. 3 * 2 = 6 , so there are a total of 6 atoms of hydrogen in 3H2O
A) Cu + 2AgNO3 ==> CuNO3 + 2Ag
1 Cu 1
2 Ag 2
2 N 1
3 O 3
The amount of nitrogen atoms is different on both sides of the equation therefore this is not a balanced equation
B) CCl4 + O2 ==> CO2 + 2Cl2
1 C 1
4 Cl 4
2 O 2
The number of atoms of each element is the same on both sides of the equation therefore this is the balanced equation, however lets check the other answer choices just in case.
C) 2K + H2SO4 ==> K2SO4 + 2H2
2 K 2
1 H 4
1 S 1
4 O 4
The number of Hydrogen atoms are different on each side of the equation therefore this is not a balanced equation.
D) 2Al2O3 ==> 2Al + 3O2
4 Al 2
6 O 6
There are a different amount of aluminum atoms on both sides of the equation therefore this is not a balanced equation.
Answer:
Such a waste of points but lol
Answer:
allows the atoms of different elements to bond together to form new substances
6 carbon atoms
H H
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3 x H - C - C - O - H
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H H
