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Elenna [48]
3 years ago
15

PLEASEEE HELP!!!

Chemistry
2 answers:
PIT_PIT [208]3 years ago
6 0

i believe it would be B '' tetrahedral compound ''

yulyashka [42]3 years ago
5 0

Answer : The correct option is, (B) Tetrahedral compound

Explanation :  

Formula used:

\text{Number of electrons}=\frac{1}{2}[V+N-C+A]

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

First we have to determine the hybridization of the CH_4 molecule.

\text{Number of electrons}=\frac{1}{2}\times [4+4]=4

The number of electrons are 4 and there is no lone pairs present on the central carbon atom that means the hybridization will be sp^3 and the electronic geometry of the molecule will be tetrahedral.

Hence, the shape of the given compound CH_4 is, tetrahedral.

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The element that appears farthest to the is written first in the chemical name of a covalent compound.
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Answer: left

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✔ left

is written first in the chemical name of a covalent compound.

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2 years ago
What determines an object’s ability to float?
Nezavi [6.7K]
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55. Which Element has a larger radius- Rb or I?
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5 0
3 years ago
Realiza los cálculos para determinar la cantidad de KOH 90%, que se necesita para preparar 100 ml de solución 1N.
attashe74 [19]

Answer:

6.23 KOH 90% son necesarios

Explanation:

Una solución 1N de KOH requiere 1equivalente (En KOH, 1eq = 1mol) por cada litro de solución.

Para responder esta pregunta se requiere hallar los equivalentes = Moles de KOH para preparar 100mL = 0.100L de una solución 1N. Haciendo uso de la masa molar de KOH y del porcentaje de pureza del KOH se pueden calcular los gramos requeridos para preparar la solución así:

<em>Equivalentes KOH:</em>

0.100L * (1eq / L) = 0.100eq = 0.100moles

<em>Gramos KOH -Masa molar: 56.1056g/mol-:</em>

0.100moles * (56.1056g/mol) = 5.61 KOH se requieren

<em>KOH 90%:</em>

5.61g KOH * (100g KOH 90% / 90g KOH) =

<h3>6.23 KOH 90% son necesarios</h3>
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