Question

PLEASEEE HELP!!!

Answer 1

i believe it would be B '' tetrahedral compound ''

Answer 2

Answer : The correct option is, (B) Tetrahedral compound

Explanation :  

Formula used:

$\text{Number of electrons}=\frac{1}{2}[V+N-C+A]$

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

First we have to determine the hybridization of the $CH_4$ molecule.

$\text{Number of electrons}=\frac{1}{2}\times [4+4]=4$

The number of electrons are 4 and there is no lone pairs present on the central carbon atom that means the hybridization will be $sp^3$ and the electronic geometry of the molecule will be tetrahedral.

Hence, the shape of the given compound $CH_4$ is, tetrahedral.