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inessss [21]
2 years ago
15

Fill in the coefficients that will balance the following reaction:

Chemistry
2 answers:
Alex17521 [72]2 years ago
3 0

Answer:

To balance a reaction, the amount of reactants must be equal to the amount of products, as stated by the Law of Conservation of Matter. It may help you to keep track of  the number of each element in a list as you try to balance. It's not able to be balanced.

REY [17]2 years ago
3 0

Answer:

2,1,1,1

Explanation:

Hope this helped!

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ACTIVIDAD 2:
Firlakuza [10]
I don’t understand your language sorry
5 0
3 years ago
A balloon filled with air has a volume of 4.24 liters at 23.00°c. if the balloon is cooled at constant pressure to 5.00°c, what
UkoKoshka [18]

The new volume if the balloon is cooled at constant pressure is  3.98 L.

Charles's law, states that the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature if the pressure remains constant.

The new  volume is calculated using the Charles law formula

                                 V₁ / T₁  = V₂ / T₂

where,

V₁ = The initial volume of air = 4.24 l

T₁ = 23.00 °C into kelvin = 23  +273 =296 K

T₂ = 5.00 °C into kelvin = 5.00 + 273 = 278 K

V₂ = ?

By making  V₂ subject the subject of the formula  by multiplying both sides by T₂

V₂ = ( V₁  × T₂ ) / T₁

V₂ =  (4.24 L  ×  278 K)  / 296 k  

   = 3.98 L

Therefore, the new volume, if the balloon is cooled at constant pressure, is  3.98 L.

An air-filled balloon will contract when chilled and expand when heated. This occurs because the gas that makes up the air within the balloon expands when it is warm and contracts when it is cool.

Learn more about Charles law here:

brainly.com/question/14842720

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7 0
1 year ago
Ben and Jerry went for a drive. They decided to stop for a snack and have some ice cream. How long did they stop at the store to
strojnjashka [21]

Answer:

The correct answer is...

A) 1/2 hour

Explanation:

5 0
3 years ago
Read 2 more answers
Please answer
timofeeve [1]

Answer:

1) petroleum, mixture, not found on periodic table

2) hydrogen and helium, mixture, contains "and"

3) iron sulphide, compound, ends with "ide"

4) carbon dioxide, compound, ends with "ide"

5) salt water, mixture, not found on periodic table

6) milk and sugar, mixture, contains "and"

7) silver nitrate, compound, ends with "ate"

8) sodium carbonate, compound, ends with "ate"

9) carbon electrode, mixture, not found on periodic table

10) astatine, element, found on periodic table

11) argon, element, found on periodic table

12) oxidane, compound, contains "ane"

13) iron and sulphur, mixture, contains "and"

14) methane, compound, contains "ane"

Explanation:

5 0
2 years ago
A 3.24-gram sample of NaHCO3 was completely decomposed in an experiment. 2NaHCO3 → Na2CO3 + H2CO3 In this experiment, carbon dio
Stolb23 [73]

Answer:

a) mass of the H2CO3 produced:

given:

Mass of sample = 3.24 g

Mass of Na2CO3 obtained after decomposition = 2.19 g

Solution :

Molar mass of NaHCO3 = 84

reaction:

2NaHCO3 → Na2CO3 + H2CO3

so it is clear that 2 mole of NaHCO3 gives 1 mole of Na2CO3 and H2CO3

Now, ICE table for the reaction is :

NaHCO3 Na2CO3 H2CO3

I 3.24/84 0 0

C -2x +x +x

E 3.24/84 -2x x x

As NaHCO3 is completely decomposed so final Concentration of NaHCO3 is zero.

=> 3.24/84 -2x = 0

=> 2x = 3.24/84

=> x = 1.62/84

The new ICE table is :

NaHCO3 Na2CO3 H2CO3

I 3.24/84 0 0

C -2x = -2(1.62/84) +x = 1.62/84 +x = 1.62/84

E 0 1.62/84 1.62/84

From the above ICE table,

it is found that (1.62/84 ) moles of H2CO3 is obtained.

Since,

The molar mass of H2CO3 is 62

=> Mass of H2CO3 obtained = moles × molar mass

=> Mass of H2CO3 obtained = (1.62 /84 ) × 62

= 1.19 grams

Mass of H2CO3 experimentally :

Mass of reactants = mass of products

=> Mass of sample = mass of Na2CO3 + mass of H2CO3

=> Mass of H2CO3 = mass of sample - mass of Na2CO3

= 3.24 - 2.19 = 1.05 g

b) Experimental mass = 1.05 g

Theoretical mass = 1.19 g

Percentage yield of H2CO3 = Experimental mass × 100 / Theoretical mass

= 1.05 × 100 /1.19

= 88.23 %

6 0
2 years ago
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