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White raven [17]
3 years ago
8

Select the correct answer. Given the data in the table, what is the average atomic mass of chlorine? A. 34.969 amu B. 35.453 amu

C. 35.9675 amu D. 36.966 amu
Chemistry
2 answers:
aksik [14]3 years ago
8 0

Answer:

B. 35.453 amu

Explanation:

The average atomic mass of chlorine as seen from the periodic table is  35.453 amu.

irinina [24]3 years ago
4 0
B 35.453 is the correct answer from what i was able to find out i hope this helps you
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How many moles of ammonia gas occupy 50 mL at at 700 kPa and 30.0 0C?
nalin [4]

For the conversions

I will start with pressure
1atm=101.3kPa
x =700kPa
x=700kPa/101.3kPa
x=6.91atm

Temperature
273K+30.00C
303K

Volume
1L=1000ml
x =50ml
x=0.05L

PV=nRT
6.91*0.05=n*0.08206*303
0.3455=24.86418n
0.3455/24.86418=n
0.0138=n
number of moles = 0.0138moles

Note: 0.08206 is the gas constant in this case
6 0
2 years ago
calculate the amount of current that must flow for 50 minutes to a solution of silver trioxonitrate (V) solution to deposit 2 mo
mamaluj [8]

Explanation:

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5 0
2 years ago
811.68 J of energy are used on a 95g chunk of unknown metal. Calculate the resulting temperature change if the specific heat of
Ivan

Answer:

16 °C

Explanation:

Step 1: Given data

  • Provided heat (Q): 811.68 J
  • Mass of the metal (m): 95 g
  • Specific heat capacity of the metal (c): 0.534 J/g.°C

Step 2: Calculate the temperature change (ΔT) experienced by the metal

We will use the following expression.

Q = c × m × ΔT

ΔT = Q/c × m

ΔT = 811.68 J/(0.534 J/g.°C) × 95 g = 16 °C

6 0
3 years ago
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Goshia [24]

Answer:

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Explanation:

7 0
2 years ago
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How many grams of CO₂ can be produced from the combustion of 2.76 moles of butane according to this equation: 2 C₄H₁₀(g) + 13 O₂
Vilka [71]

Answer:

485.76 g of CO₂ can be made by this combustion

Explanation:

Combustion reaction:

2 C₄H₁₀(g) + 13 O₂ (g) → 8 CO₂ (g) + 10 H₂O (g)

If we only have the amount of butane, we assume the oxygen is the excess reagent.

Ratio is 2:8. Let's make a rule of three:

2 moles of butane can produce 8 moles of dioxide

Therefore, 2.76 moles of butane must produce (2.76 . 8)/ 2 = 11.04 moles of CO₂

We convert the moles to mass → 11.04 mol . 44g / 1 mol = 485.76 g

5 0
3 years ago
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