Answer:
1. observational
2. clinical trial
*3. meta analysis*
Explanation:
Hopefully this is correct but if its not I apoligize
Answer:
//Function is written using C++ Programming Language
// Comments are used for explanatory purpose
// The main method is not included
using namespace std;
// Declare arraySum with two arguments. The first represents the array name while the other
// Represents the number of elements
int arraySum(int arr[], int n)
{
int total = 0; // declare and Initialise total to 0
// Iterate through the array to calculate sum
for (int i = 0; i < n; i++) {
total += arr[i];
}
return total;
}
Answer:
7.65 mm
Explanation:
Stress,
where F is the force and A is the area
Also, ![\sigma=E\times \frac {\triangle L}{L}](https://tex.z-dn.net/?f=%5Csigma%3DE%5Ctimes%20%5Cfrac%20%7B%5Ctriangle%20L%7D%7BL%7D)
Where E is Young’s modulus, L is the length and
is the elongation
Therefore,
![\frac {F}{A}= E\times \frac {\triangle L}{L}](https://tex.z-dn.net/?f=%5Cfrac%20%7BF%7D%7BA%7D%3D%20E%5Ctimes%20%5Cfrac%20%7B%5Ctriangle%20L%7D%7BL%7D)
Making A the subject of the formula then
![A=\frac {FL}{E\triangle L}=\frac {6660\times 380}{110\times 10^{9}\times 0.5}=4.60145\times 10^{-5} m^{2}](https://tex.z-dn.net/?f=A%3D%5Cfrac%20%7BFL%7D%7BE%5Ctriangle%20L%7D%3D%5Cfrac%20%7B6660%5Ctimes%20380%7D%7B110%5Ctimes%2010%5E%7B9%7D%5Ctimes%200.5%7D%3D4.60145%5Ctimes%2010%5E%7B-5%7D%20m%5E%7B2%7D)
Since
then
![d=\sqrt {\frac {4A}{\pi}}=\sqrt {\frac {4\times 4.60145\times 10^{-5}}{\pi}}= 0.00765425m= 7.654249728 mm\approx 7.65 mm](https://tex.z-dn.net/?f=d%3D%5Csqrt%20%7B%5Cfrac%20%7B4A%7D%7B%5Cpi%7D%7D%3D%5Csqrt%20%7B%5Cfrac%20%7B4%5Ctimes%204.60145%5Ctimes%2010%5E%7B-5%7D%7D%7B%5Cpi%7D%7D%3D%200.00765425m%3D%207.654249728%20mm%5Capprox%207.65%20mm)
The air leaving through the balloon's mouth pulls the balloon in the same direction as the exiting air, so the balloon experiences a net force. All air surrounding the balloon pushes the balloon forward.
Answer:429.8 KW
Explanation:
carbon dioxide Inlet temperature
and pressure 100 KPa
At given Temperature and presssure ![c_p_1=0.846 kJ/kg-k](https://tex.z-dn.net/?f=c_p_1%3D0.846%20kJ%2Fkg-k)
Flow rate ![\dot{m} =1.5 kg/s](https://tex.z-dn.net/?f=%5Cdot%7Bm%7D%20%3D1.5%20kg%2Fs)
Steam Outlet temperature and Pressure is
and pressure is 600 KPa
![c_p_2=1.014 kJ/kg-k](https://tex.z-dn.net/?f=c_p_2%3D1.014%20kJ%2Fkg-k)
Heat loss 50 KW
Applying Steady Flow Energy Equation
![\dot{m}\left ( h_1+\frac{v_1^2}{2}+z_1 \right )+\dot{Q}=\dot{m}\left ( h_2+\frac{v_2^2}{2}+z_2 \right )+\dot{W}](https://tex.z-dn.net/?f=%5Cdot%7Bm%7D%5Cleft%20%28%20h_1%2B%5Cfrac%7Bv_1%5E2%7D%7B2%7D%2Bz_1%20%5Cright%20%29%2B%5Cdot%7BQ%7D%3D%5Cdot%7Bm%7D%5Cleft%20%28%20h_2%2B%5Cfrac%7Bv_2%5E2%7D%7B2%7D%2Bz_2%20%5Cright%20%29%2B%5Cdot%7BW%7D)
Neglecting Kinetic and Potential Energy changes
![\dot{m}h_1+\dot{Q}=\dot{m}h_2+\dot{W}](https://tex.z-dn.net/?f=%5Cdot%7Bm%7Dh_1%2B%5Cdot%7BQ%7D%3D%5Cdot%7Bm%7Dh_2%2B%5Cdot%7BW%7D)
![\dot{W}=\dot{m}\left ( c_p_1T_1-c_p_2T_2\right )+\dot{Q}](https://tex.z-dn.net/?f=%5Cdot%7BW%7D%3D%5Cdot%7Bm%7D%5Cleft%20%28%20c_p_1T_1-c_p_2T_2%5Cright%20%29%2B%5Cdot%7BQ%7D)
![\dot{W}=1.5\left ( 0.846\times 300-1.014\times 500\right )-50](https://tex.z-dn.net/?f=%5Cdot%7BW%7D%3D1.5%5Cleft%20%28%200.846%5Ctimes%20300-1.014%5Ctimes%20500%5Cright%20%29-50)
![\dot{W}=429.8 KW](https://tex.z-dn.net/?f=%5Cdot%7BW%7D%3D429.8%20KW)
Negative sign indicates work is being done on the system.