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VARVARA [1.3K]
3 years ago
6

An advantage presented by Straight in space is that___.

Engineering
1 answer:
gizmo_the_mogwai [7]3 years ago
5 0
Traditional straight parking spaces allow for a more flexible traffic layout since a driver can approach the spot from either direction and still safely park within the lines. ... If the cars are able to move in and out, and through the parking lot lanes faster than this will lead to less congestion.
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State two reasons why industrial files must be always be used fitted upon the individual
NikAS [45]

Explanation:

dnndndndndndndndndnndmfnfnf

4 0
3 years ago
What are materials engineers trying to discover when they study different materials?
coldgirl [10]
What do materials science and engineering graduates do?
Almost two-thirds of materials science graduates are in employment six months after graduation.

The skills developed during a materials science degree allow graduates enter a range of sectors, including working as engineering professionals and in design and marketing roles.

Destination Percentage
Employed 60.4
Further study 24.5
Working and studying 5.1
Unemployed 4
Other 6.1
Graduate destinations for materials science and engineering
Type of work Percentage
Engineering and building 23.9
Marketing, PR and sales 11.9
Business, HR and financial 11.7
Technicians and other professionals 10
Other 42.5
5 0
3 years ago
Read 2 more answers
a centrifugal pump delivers water at the rate of 50kg/is . the inlet and outlet pressure are 2 bar and 6.2 bar respectively. the
Monica [59]

Answer:

21.6 kw

Explanation:

Given data:

m = 50 kg/s

Inlet pressure (p1) = 2 bar

outlet pressure(p2) = 6.2 bar

suction ( h1 ) = -2.2 m

delivery ( h2 ) = 8.5 m

d1 = 200 mm = 0.2 m

d2 = 100 mm = 0.1 m

Vs of water = 0.001 m^3/kg

next we have to determine the Q value

Q = V*A

Q = 0.001 * 50 = 0.05 m^3/s

next we have to calculate the various V's

V1 = Q/A1 = \frac{0.05*4}{\pi *0.2^2}  = 1.59 m/s

V2 = Q/A2 = \frac{0.05*4}{\pi *0.1^2} = 6.37 m/s

Determine the capacity of the electric motor

attached below is the detailed solution

7 0
3 years ago
Calculate KI for a rectangular bar containing an edge crack loaded in three-point bending where P=35.0 kN, W=50.8 mm, B=25 mm, a
Katyanochek1 [597]

Answer:

K_{I}=5.21 MPa\sqrt{m}

Explanation:

given data

Load P = 35 kN

Width of bar W = 50.8 mm

Breadth of bar B = 25 mm

Ratio of crack length to width α = a/W = 0.2

solution

we get here KI for a rectangular bar that is express as

K_{I} = \frac{6P}{BW}Y\sqrt{\pi a}   ................................1

here Y is the geometrical function

so

Y = \frac{1.12+\alpha (3.43\alpha -1.89)}{1-0.55\alpha}

Y = \frac{1.12+0.2(3.43\times 0.2-1.89)}{1-0.55\times 0.2}  

Y = \frac{0.8792}{0.89}  

Y = 0.9878

so put here value in equation 1

K_{I} = \frac{6\times 35\times 10^{3}}{0.025\times 0.0508}\times 0.9878\times \sqrt{3.1415\times (0.2\times 0.0508)}    

K_{I} = 165354.33\times 10^{3}\times 0.9878\times 0.0319

K_{I} = 5210.45 × 10³  Pa\sqrt{m}  

K_{I} = 5.21 MPa \sqrt{m}

5 0
3 years ago
In an analog addressable system, the determination of the alarm state is performed by the _____?
Nostrana [21]

Answer:

Control panel

Explanation:

The Control Panel is a component of Microsoft Windows which provides the ability to view and change system settings. It consists of a set simple computer programs (applets) that include adding or removing hardware and software, controlling user accounts, changing accessibility options, and accessing networking settings.

6 0
3 years ago
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