The oxidation number<span> of a Group 2 element in a </span>compound<span> is +2. The </span>oxidation number<span> of a Group 17 element in a binary </span>compound<span> is -1. The sum of the </span>oxidation numbers<span> of all of the atoms in a neutral </span>compound<span> is 0. The sum of the </span>oxidation numbers<span> in a polyatomic ion is equal to the charge of the ion.</span>
Answer:
The (H30+) is 4,13x10-8
Explanation:
We use the formula
Kwater = (H30 +) x (OH-)
1.00e-14 = (H30 +) x 2.42e-7
(H30 +) = 1.00e-14 / 2.42e-7 = 4.13e-8M
That is True XD
Hope that helps :D
The aluminum can with stand <span>0.942 J° C of heat </span>
